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Olin [163]
3 years ago
5

A person works 40 hours per week earns 59,70 per year, estimate that persons hourly wage by rounding to the nearest ten thousand

. Use the estimate that there are 50 weeks in the year
Mathematics
1 answer:
olganol [36]3 years ago
8 0

Answer:

he earns about 120 bucks a week

Step-by-step explanation:

There are 168 hours in a week and, so if the hours in 5970 divided by 50 equals 119.4 (possibly irrelevant) but if he gets paid 5970 per year and works 0.57 hours per day (40 divided by 24) and works about 1.666_ days a week than that would equal 120.85

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Show that √(1-cos A/1+cos A) =cosec A - cot A​
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Hi there!

\sqrt{\frac{1-cosA}{1+cosA}} =

We can begin by multiplying by its conjugate:

\sqrt{\frac{1-cosA}{1+cosA}} * \sqrt{\frac{1+cosA}{1+cosA}}  = \\\\\sqrt{\frac{(1-cosA)(1 + cosA)}{(1+cosA)(1 + cosA)}} =

Simplify using the identity:

1 - cos^2A = sin^2A

\sqrt{\frac{(1-cos^2A)}{(1+cosA)^2}} =\\\\\sqrt{\frac{(sin^2A)}{(1+cosA)^2}} =

Take the square root of the expression:

{\frac{sinA}{1+cosA} =

Multiply again by the conjugate to get a SINGLE term in the denominator:

{\frac{sinA}{1+cosA} * {\frac{1-cosA}{1-cosA} =\\

Simplify:

{\frac{sinA(1-cosA)}{1-cos^2A} =

Use the above trig identity one more:

{\frac{sinA(1-cosA)}{sin^2A} =

Cancel out sinA:

{\frac{(1-cosA)}{sinA}  =

Split the fraction into two:

{\frac{1}{sinA}   - \frac{cosA}{sinA} =

Recall:

1/sinA = cscA\\\\cosA/sinA = cotA

Simplify:

\frac{1}{sinA} + \frac{cosA}{sinA} = \boxed{cscA - cotA}

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