Which represents the solution(s) of the system of equations, y = x^2 - 6x + 8 and y = -x + 4? Determine the solution set by grap
hing
(1,3) only
(2,0) and (4,0)
(1, 3) and (4,0)
no solutions
(1,3) only
(2,0) and (4,0)
(1, 3) and (4,0)
no solutions
1 answer:
Answer:
(1, 3) and (4,0)
Step-by-step explanation:
The quadratic function is
We can rewrite in the form
The graph is obtained by shifting the parent quadratic function 3 units right and 1 unit down to obtain the parabola shown in the attachment.
The straight line also have equation
The slope is -1 and y-intercept is 4.
We can easily graph this straight line on the same graph as shown in the attachment.
The two graphs intersected at (4,0) and (1,3).
The solution set is therefore {(x,y)|x=4,y=0 or x=1,y=3}
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The first year, the amount is 40,000
the second year is 40000 + 4.2% of 40000, or 0.042 * 4000, so 40000+(0.042*4000)
common factoring that we get 40000(1 + 0.042), or just 40000(1.042)
in short, the starting amount is 40000, and to get the next term's value you'd use the "common ratio" of 1.042, namely the multiplier of 1.042.
for the third year it'll be 40000(1.042) + (0.042 *40000(1.042) ), again, common factoring that
40000(1.042)(1 + 0.042) or 40000(1.042)(1.042) or 40000(1.042)²
therefore,
the second year is 40000 + 4.2% of 40000, or 0.042 * 4000, so 40000+(0.042*4000)
common factoring that we get 40000(1 + 0.042), or just 40000(1.042)
in short, the starting amount is 40000, and to get the next term's value you'd use the "common ratio" of 1.042, namely the multiplier of 1.042.
for the third year it'll be 40000(1.042) + (0.042 *40000(1.042) ), again, common factoring that
40000(1.042)(1 + 0.042) or 40000(1.042)(1.042) or 40000(1.042)²
therefore,