I will give brainlist and the go to together not to questions

Bill is building a model of a square pyramid for a class project. The side length of the square base is 10 inches and the slant

Zolol [24]

The surface area for the square pyramid is A= 416.23

6 0

3 years ago

Read 2 more answers

Sean is driving to visit his friend in another state.In the first hour he travels 1/5 of the total distance. In the second hour

lozanna [386]

Answer:

They live 285 miles apart

Step-by-step explanation:

Let the total distance be x miles

Sean is driving to visit his friend in another state. In the first hour he travels 1/5 of the total distance. This means that he drove x/5 in the first hour. In the second hour he travels 34 miles. That means

Total distance driven in the first and second hour is

(x/5 + 34)miles

He still has 194 miles more to go.

Therefore,

The total distance is the sum of the distance travelled in the first and second hour + the remaining distance.

x = x/5 + 34 + 194

x = x/5 + 228

Cross multiplying

5x = x + 1140

4x = 1140

x = 1140/4 = 285 miles

7 0

3 years ago

Someone please help!!

Bumek [7]

Answer:

I believe the answer would be option D

Step-by-step explanation:

the distance formula is

$\sqrt{(x - x1)^{2} + (y - y1)^{2} }$

So, substituting the values of the coordinates, you will get the answer of D

4 0

2 years ago

In a particular course, it was determined that only 70% of the students attend class on Fridays. From past data it was noted tha

siniylev [52]

Answer: Probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

Step-by-step explanation:

Since we have given that

Probability that students attend class on Fridays = 70% = 0.7

Probability that who went to class on Fridays would pass the course = 95% = 0.95

Probability that who did not go to class on Fridays would passed the course = 10% = 0.10

Let A be the event students passed the course.

Let E be the event that students attend the class on Fridays.

Let F be the event that students who did not attend the class on Fridays.

Here, P(E) = 0.70 and P(F) = 1-0.70 = 0.30

P(A|E) = 0.95, P(A|F) = 0.10

We need to find the probability that they did not attend on Fridays.

We would use "Bayes theorem":

$P(F\mid A)=\dfrac{P(F).P(A\mid F)}{P(E).P(A\mid E)+P(F).P(A\mid F)}\\\\P(F\mid A)=\dfrac{0.30\times 0.10}{0.70\times 0.95+0.30\times 0.10}\\\\P(F\mid A)=\dfrac{0.03}{0.695}=0.043$

Hence, probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

8 0

3 years ago

What is the parent function of the following function?<br> f(x) = 3(5)*

Vlad [161]

I think it’s 15 f(x) 15

7 0

3 years ago