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omeli [17]
3 years ago
11

Jada asked some students at her school how many hours they spent watching television last week, to the nearest hour. Here are a

box plot and a histogram for the data she collected.
If anyone trolls imma be very sad :(
Mathematics
1 answer:
-Dominant- [34]3 years ago
3 0

Answer:

100

Step-by-step explanation:

Based on the histogram given :

The vertical axis gives the number of student in the school :

For the range :

0 - 5 = 40

5 - 10 = 30

10 - 15 = 20

15 - 20 = 5

20 - 25 = 3

25 - 30 = 2

Taking the sum :

(40 + 30 + 20 + 5 + 3 + 2) = 100

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As a promotion, a clothing store draws the name of one of its customers each week. The prize is a coupon for the store. If the w
kompoz [17]

The given formula is f(x) = 20(1.2)^x

The formula is the starting amount multiplied by 1 + the percentage raised to the number of weeks.


A) the percent increase is 20% ( 1.2 in the formula is 1 +20% as a decimal)

B) the original amount is $20

C) for 2 weeks, replace x with 2 and solve:

20(1.2)^2

20(1.44) = $28.80

After 2 weeks the coupon is $28.80

D)  To solve for the number of weeks (x) set the equation equal to $100:

100 = 20(1.2)^x

Divide both sides by 20:

5 = 1.2^x

Take the natural logarithm of both sides:

ln(5) = ln(1.2^x)

Use the logarithm rule to remove the exponent:

ln(5) = x ln(1.2)

Divide both sides by ln(1.2)

x = ln(5) / ln(1.2)

Divide:

X = 8.83

At 8.83 weeks the coupon would be $100, so after 9 weeks the coupon would be greater than $100

The answer is 9 weeks.

4 0
3 years ago
What is the area, in square yards, of the polygon shown?
Alexeev081 [22]

Answer:46


Step-by-step explanation:Regular polygons are shapes made of straight lines with certain relationships among their lengths. For instance, a square has 4 sides, all the same length. A regular pentagon has 5 sides, all the same length. For these shapes, there are formulas for finding the area. But for irregular polygons, which are made of straight lines of any length, there are no formulas, and you need to be a little creative to find the area. Fortunately, any polygon may be divided into triangles, and there is a simple formula for the area of triangles.


Label the vertices (points) of the polygon starting with 1 at an arbitrary vertex and continuing clockwise around the polygon. There should be as many vertices as there are sides. E.g. for a pentagon (five sides) there will be five vertices.


Draw a line from vertex 1 to vertex 3. This will make one triangle, with vertices 1, 2, and 3. If there are only 4 sides, it will also make a triangle with vertices 1, 3 and 4.If the polygon has more than 4 sides, draw a line from vertex 3 to vertex 5. Continue in this way until you run out of vertices.


Compute the area of each triangle. The formula for the area of a triangle is 1/2 * b * h, where b is the base and h is the height.


Add up the areas, and this is the area of the polygon.

3 0
3 years ago
Read 2 more answers
It takes 11 ounces of oatmeal to make 1 serving. How many servings are
Rzqust [24]

Answer:

I think its 1.56

Step-by-step explanation:

if its right can I please get the brainlest

5 0
3 years ago
Alex needs 80 cm of thread for a sewing project. The thread is on a spool with a circumference of 10 cm. How many times must ale
Mrrafil [7]

<u>Answer:</u>

If the spool has 10 cm of circumference or perimeter, this means that 10 cm of thread fits the whole circumference of the spool, which also means that

<h2>1 unwind is equivalent to 10 cm of thread. </h2>

Then, we have to make the following question:

If 10 cm of thread is equivalent to 1 unwind, to how many unwinds is equivalent 80 cm of thread?

If we want to know how many time does Alex need to unwind the spool, we can use the following relation also called the <u>Rule of Three: </u>

<u> </u>

10 cm----1 unwind

80 cm----X unwinds

X=\frac{80cm(1unwind)}{10cm}

X=8unwinds

The answer is:

Alex must unwind the spool 8 times in order to get 80 cm of thread


5 0
3 years ago
How do you find the surface area of a composite figure?
Mekhanik [1.2K]

A composite figure is a figure made up of simple shapes. To find the total surface area of a composite figure, you break up the composite figure into simple shapes whose surface areas you can find using existing formulas. Then you add all the areas of the simple shapes to find the total surface area of the composite figure.

The figure in this problem is a cylinder with a cone on top. The visible areas are: 1) The lower base of the cylinder; 2) The lateral area of the cylinder (the vertical wall all around the cylinder); 3) The lateral area of the cone.

The base of the cone and top base of the cylinder are not visible because they are interior to the composite figure. We only have the three surfaces described above to calculate and add together.

1) The lower base of the cylinder is a circle. We use the formula for the area of a circle using a radius of 4 cm.

A_{circle} = \pi r^2 = \pi \times (4~cm)^2 = 16 \pi~cm^2

2) The lateral area of the cylinder is the area of a rectangle whose length is the circumference of the base and whose width is the height of the cylinder.

A_{lateral~rectanlge} = LW = 2 \pi r \times h = 2 \pi (4~cm)(8~cm) = 64\pi~cm^2

3) The lateral area of the cone is given by the formula:

A_{lateral~cone} = \pi r \sqrt{r^2 + h^2}

A_{lateral~cone} = \pi \times (4~cm)\sqrt{(4~cm)^2 + (5~cm)^2}

A_{lateral~cone} = 4 \pi \sqrt{41} ~cm^2

To find the total surface area, we add the three surface areas we found above.

A = 16 \pi~cm^2 + 64\pi~cm^2 + 4 \pi \sqrt{41} ~cm^2

The exact area is:

A = (80 + 4 \sqrt{41})\pi ~cm^2

The approximate area in terms of pi is:

A = 105.6 \pi~cm^2

7 0
3 years ago
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