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STatiana [176]
3 years ago
12

a 2.00 kg object is moving east at 4.00 m/s when it collides with a 6 kg object that is initially at rest. after the collision t

he larger object moves east at 1 m/s. what is the final velocity of the smaller object after the collision
Physics
1 answer:
baherus [9]3 years ago
6 0

Answer:

v = 1.00 m/s east

Explanation:

Conservation of momentum

Let east be the positive direction

2.00(4.00) + 6.00(0.00) = 2.00(v) + 6.00(1.00)

v = 1.00 m/s east

The two items have stuck together.

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plsssssss i need help Which source of law is most like common law: statutes, case law, or administrative law? Explain
Lisa [10]

Answer:

The answer is "case law".

Explanation:

This law is not based on law, but on legislatures, statutes, or legislation, on judgments. Its also used as a different term with common law, which is the collection of precedents as well as power on a specific subject established in previous judicial decisions that are a part of Common law, which is also recognized as case law to establish by the court system based on legal case law.

7 0
3 years ago
What force is needed to give a 0.25-kg arrow an acceleration of 196 m/s/s
kakasveta [241]
Force (f) = ?

Acceleration (a) = 196 m/s^2

Mass (m) = 0.25 kg

F = (m) • (a)

F = (0.25) • (196)

F = 49 N

Answer : 49 N

I hope that helps you!! Any more questions??

8 0
3 years ago
Read 2 more answers
Can someone explain to me #4.
nalin [4]
A) We balance the masses: 4(1.00728) vs 4.0015 + 2(0.00055)4.02912 vs. 4.0026This shows a "reduced mass" of 4.02912 - 4.0026 = 0.02652 amu. This is also equivalent to 0.02652/6.02E23 = 4.41E-26 g = 4.41E-29 kg.
b) Using E = mc^2, where c is the speed of light, multiplying 4.41E-29 kg by (3E8 m/s)^2 gives 3.96E-12 J of energy.
c) Since in the original equation, there is only 1 helium atom, we multiply the energy result in b) by 9.21E19 to get 3.65E8 J of energy, or 365 MJ of energy.
4 0
3 years ago
Can lamp that works on a 2.5 v work on a 1.12 v ?​
12345 [234]

Answer:

Explanation:

Thinking about the logics it can but it may be dim because 1.12 is lower than 2,5v so this will mean u lamp may not work or may work very dimely due to the low voltage it is receiving.

5 0
3 years ago
The maximum wavelength an electromagnetic wave can have and still eject an electron from a copper surface is 264 nm .What is the
Tamiku [17]

Answer:

4.71 eV

Explanation:

For an electromagnetic wave with wavelength

\lambda=264 nm = 2.64\cdot 10^{-7} m

the energy of the photons in the wave is given by

E=\frac{hc}{\lambda}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{2.64\cdot 10^{-7}m}=7.53\cdot 10^{-19} J

where h is the Planck constant and c the speed of light. Therefore, this is the minimum energy that a photon should have in order to extract a photoelectron from the copper surface.

The work function of a metal is the minimum energy required by the incident light in order to extract photoelectrons from the metal's surface. Therefore, the work function corresponds to the energy we found previously. By converting it into electronvolts, we find:

E=\frac{7.53\cdot 10^{-19} J}{1.6\cdot 10^{-19} J/eV}=4.71 eV

3 0
3 years ago
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