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STatiana [176]
3 years ago
12

a 2.00 kg object is moving east at 4.00 m/s when it collides with a 6 kg object that is initially at rest. after the collision t

he larger object moves east at 1 m/s. what is the final velocity of the smaller object after the collision
Physics
1 answer:
baherus [9]3 years ago
6 0

Answer:

v = 1.00 m/s east

Explanation:

Conservation of momentum

Let east be the positive direction

2.00(4.00) + 6.00(0.00) = 2.00(v) + 6.00(1.00)

v = 1.00 m/s east

The two items have stuck together.

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The boundary between tectonic plates that are moving toward each other
Alisiya [41]

Answer:

A divergent boundary is the answer

Explanation:

4 0
4 years ago
A proton moving at 8.9 × 106 m/s through a magnetic field of 0.96 T experiences a magnetic force of magnitude 3.8 × 10−13 N. Wha
goblinko [34]

Answer: 15.66 °

Explanation: In order to solve this proble we have to consirer the Loretz force for charge partcles moving inside a magnetic field. Thsi force is given by:

F=q v×B = qvB sin α where α is teh angle between the velocity and magnetic field vectors.

From this expression and using the given values we obtain the following:

F/(q*v*B) = sin α

3.8 * 10^-13/(1.6*10^-19*8.9*10^6* 0.96)= 0.27

then  α =15.66°

8 0
3 years ago
A student standing on a knoll throws a snowball horizontally 4.5 meters above the level ground toward a smokestack 15 meters awa
Elan Coil [88]

Answer:

2.4 m

Explanation:

Consider the motion along the vertical direction

y_{o} = initial position of ball above the ground = 4.5 m

t = time taken by the ball to hit the smokestack = 0.65 s

v_{oy} = initial velocity of the ball along vertical direction

a_{y} = acceleration due to gravity = - 9.8 m/s²

y = position of ball at the time of hitting the smokestack

Using the kinematics equation

y = y_{o} + v_{oy} t + (0.5) a_{y} t^{2}

inserting the above values

y = 4.5 + (0) (0.65) + (0.5) (- 9.8) (0.65)^{2} \\y = 2.4 m

6 0
3 years ago
A 0.10 newton spring toy with a spring constant of 160 newtons per meter is compressed 0.05 meter before it is launched. When re
forsale [732]

Answer:

(1) V = 0.2 J (2) 0.05J

Explanation:

Solution

Given that:

K = 160 N/m

x = 0.05 m

Now,

(1) we solve for the  initial potential energy stored

Thus,

V = 1/2 kx² = 0.5 * 160 * (0.05)²

Therefore V = 0.2 J

(2)Now, we solve for how much of the internal energy is produced as the toy springs up to its maximum height.

By using the energy conversion, we have the following

ΔV = mgh

=(0.1/9.8) * 9.8 * 1.5 = 0.15J

The internal energy = 0.2 -0.15

=0.05J

8 0
3 years ago
A little girl kicks a soccer ball. It goes 10 feet and comes back to her. How is this possible?
marta [7]
A classic puzzle...

She either kicked it at a wall <em>exactly</em><em /> 10 foot in front of her, where the ball rebounded off the wall.

Or, she kicked the ball straight up, vertically, at a <em>90 degree angle,</em> where due to the law of gravity, which states that anything that goes up must come down, when the soccer ball reaches exactly 10 feet, it falls back down.
(Note: This is nearly impossible to achieve -- exactly 10 feet.)

8 0
4 years ago
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