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aliina [53]
4 years ago
8

A ball having a weight of 1.5 N is dropped from a height of 4 meters. (Neglect air friction.) How much mechanical energy is "los

t" just before it hits the ground?
Physics
2 answers:
mafiozo [28]4 years ago
6 0
If there is no air resistance, then NO energy is 'lost'.

At the height of 4 meters above the ground, the ball has

                    (weight) x (height) 
                =    (1.5 N) x (4 m) 

                =         6 joules

of gravitational potential energy, relative to the ground.

If it's dropped, then the potential energy it has gets converted
to kinetic energy all the way down. 

Just before it hits the ground, it has no more potential energy,
but it has 6 joules of kinetic energy.

No energy is lost.  It just changes from potential to kinetic.
Both of them are forms of mechanical energy.
NikAS [45]4 years ago
4 0
As this mechanical energy is associated with height, it would be "Potential Energy" in particular.

U = mgh
U = F.h
U = 1.5 * 4
U = 6 Joules

So, 6 J of energy is lost before it hits the ground.

Hope this helps!
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Explanation:

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The volume is directly proportional to the pressure. Therefore, as the temperature drops the volume will also decrease.

V α T

This is also known as the Charles Law.

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Select the statements that correctly interpret the data in this heating curve.
tekilochka [14]

The consistent temperature indicated by section 2 represents the flow of energy lost as the water freezes.

Section 2 indicates that energy is being utilized to bring all molecules to the melting point.

Section 4 indicates that the temperature is stable until all molecules reach the boiling point.

The increasing temperature in section 5 indicates that molecular motion is increasing.

Explanation:

The figure is missing: find it in attachment.

The graph represents the temperature of a block of ice as heat is continuously supplied to it.

At the beginning (section 1), the temperature increases: in this phase, the heat supplied to the ice is used to increase the kinetic energy of vibration of the molecules of ice.

When the ice reach point A (melting point), the ice starts to melt. In this phase (section 2), the temperature of the substance remains constant, because all the heat supplied is used to break the bonds between the molecules, converting the ice into liquid water.

At point B, the ice has completely melted, and therefore we now have liquid water.

In sector 3 (between B and C), the temperature of the water increases again as we supply more and more heat: this heat, in fact, is used to increase the kinetic energy of the molecules, which move faster and faster.

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Section 2 indicates that energy is being utilized to bring all molecules to the melting point.

Section 4 indicates that the temperature is stable until all molecules reach the boiling point.

The increasing temperature in section 5 indicates that molecular motion is increasing.

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