Ask question

Ask question

All categories

3 years ago

10

Is it possible for a stationary object to have a single force acting not it? If your answer is yes, provide and example. If your

answer is no, explain why not.

2 answers:

tia_tia [17]3 years ago

4 0

الله ينطيك that’s why

Kisachek [45]3 years ago

3 0

Yes for example a book is sitting on a desk it will have a force of gravity pulling it downwards

You might be interested in

Explain when acceleration remains constant.

stellarik [79]

Explanation:

acceleration remains constant when velocity does not increase or decrease

6 0

3 years ago

Please help ASAP.

Bess [88]

Im not 100% sure you have to tell me if im wrong or not.

D

B

C

3 0

3 years ago

Read 2 more answers

A cannonball is catapulted toward a castle. The cannonball’s velocity when it leaves the catapult is 51.6 m/s at an angle of 37.

Andrei [34K]

Answer:

$v_{y}=35.21m/s$

Explanation:

From the exercise we know the cannonball's <u>initial velocity</u>, the <u>angle</u> which its released with respect to the horizontal and its <u>initial height</u>

$v_{o}=51.6m/s\\\beta =37.0º\\y_{o}=7m$

If we want to know whats the <u>y-component of velocity</u> we need to use the following formula:

$v_{y}^2=v_{oy}^2+ag(y-y_{o})$

Knowing that $g=-9.8m/s^2$

$v_{y}=\sqrt{((51.6m/s)sin(37))^2-2(9.8m/s^2)(0m-7m)}=35.21m/s$

So, the cannonball's y-component of velocity is $v_{y}=35.21m/s$

6 0

3 years ago

What is the approximate percentage change in the Earth-Sun distance between June 21 and December 21?

tia_tia [17]

For the purpose of the exercise, we can assume that the Earth is at perihelion (closest point to the Sun) on December 21st (in reality, it happens around January 4th) and that the Earth is at aphelion (farthest point from the Sun) on June 21st (in reality, this happens around July 4th). The distance Earth-Sun is the following:
- Perihelion: 147.1 milion km
- Aphelion: 152.1 milion km
- Average distance: 149.6 milion km
So, we can calculate the percentage change with respect to the average distance as:
$d= \frac{d(aphelion)-d(perihelion)}{d(average)}\cdot 100= \frac{152.1-147.1}{149.6}\cdot 100=3.3 \%$

5 0

3 years ago

Could an average star, such as our sun, become a neutron star?

algol [13]

No but the sun could be a white dwarf stellar remnant.

3 0

4 years ago