I think it would be something like this: x-80 = (x*2)+12
Answer:
11
Step-by-step explanation:
divide 209 by 19 to get an equal number of games each month (for 19 months), you will get 11 games each month.
Answer:
(-6, 6)
Step-by-step explanation:
The coordinates of B to start with is
(-2, 2)
To dilate this by a factor of 3....
-2 * 3 = -6
2 * 3 = 6
The new coordinates of B' would be
(-6, 6)
A few things to know:
- The number 3 is called a "<u>scale factor</u>"
- Dilation means we are multiplying all the (X, Y)'s by the scale factor
- If the scale factor is <u>greater than 1</u>, the size of the shape overall increases
- If the scale factor is <u>less than 1</u>, the size of the shape overall decreases
- If the scale factor is <u>negative</u>, the shape size stays the same. The shape just rotates 180 degrees and moves to the opposite quadrant.
Answer:
a) The percentage of athletes whose GPA more than 1.665 is 87.49%.
b) John's GPA is 3.645.
Step-by-step explanation:
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
a)Find the percentage of athletes whose GPA more than 1.665.
This is 1 subtracted by the pvalue of Z when X = 1.665. So
has a pvalue of 0.1251
1 - 0.1251 = 0.8749
The percentage of athletes whose GPA more than 1.665 is 87.49%.
b) John's GPA is more than 85.31 percent of the athletes in the study. Compute his GPA.
His GPA is X when Z has a pvalue of 0.8531. So it is X when Z = 1.05.
John's GPA is 3.645.
Evaluate 2x − 2 for x = 0, x = 1, and x = 2. Question 1 options: A) −1, 0, 2 B) −1, 1, 2 C) 0, 1, 2 D) 1, 2, 4
mixas84 [53]
The value of x in 2^x - 2 when x = 0, x = 1 and x = 2 are -1, 0 and 2 respectively. option A
<h3>Algebra</h3>
2^x - 2
when x = 0
2^x - 2
= 2^0 - 2
= 1 - 2
= -1
when x = 1
2^x - 2
=2^1 - 2
= 2 - 2
= 0
when x = 2
2^x - 2
= 2^2 - 2
= 4 - 2
= 2
Learn more about algebra:
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