We are given –
- Mass of
is 57.1 g and we are asked to find number of moles present in 57.1 g of ![\bf N_2](https://tex.z-dn.net/?f=%20%5Cbf%20N_2)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\pink{\bf\longrightarrow { Molar \:mass \:of \: N_2:-} }](https://tex.z-dn.net/?f=%20%5Cpink%7B%5Cbf%5Clongrightarrow%20%20%7B%20Molar%20%5C%3Amass%20%5C%3Aof%20%5C%3A%20N_2%3A-%7D%20%20%7D)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\bf \twoheadrightarrow 14\times 2](https://tex.z-dn.net/?f=%20%5Cbf%20%20%5Ctwoheadrightarrow%2014%5Ctimes%202%20)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\bf \twoheadrightarrow 28](https://tex.z-dn.net/?f=%20%5Cbf%20%5Ctwoheadrightarrow%20%20%2028)
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Now,Let's calculate the number of moles present in 57.1 g of ![\bf N_2](https://tex.z-dn.net/?f=%20%5Cbf%20N_2)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\purple{\bf\longrightarrow { No \:of \:moles = \dfrac{Given \:mass}{Molar\: mass}}}](https://tex.z-dn.net/?f=%20%5Cpurple%7B%5Cbf%5Clongrightarrow%20%20%7B%20No%20%5C%3Aof%20%5C%3Amoles%20%3D%20%5Cdfrac%7BGiven%20%5C%3Amass%7D%7BMolar%5C%3A%20mass%7D%7D%7D)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\bf \twoheadrightarrow \dfrac{57.1}{28}](https://tex.z-dn.net/?f=%20%5Cbf%20%20%20%5Ctwoheadrightarrow%20%5Cdfrac%7B57.1%7D%7B28%7D)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\bf \twoheadrightarrow 2.04\: moles](https://tex.z-dn.net/?f=%20%5Cbf%20%20%5Ctwoheadrightarrow%202.04%5C%3A%20moles)
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The 02 is a solid. I hope thus helped you :)
I believe it is the second option
<u>Given:</u>
Mass of the ball = 35.2 kg
Momentum = 218 kg m/s
<u>To determine:</u>
The velocity of the ball
<u>Explanation:</u>
Momentum (p) of an object is the product of its mass (m) and velocity (v)
p = m*v
v = p/m = 218 kg.ms-1/35.2 kg = 6.19 m/s
Ans: The velocity of the ball is 6.19 m/s