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3 years ago

15

Everything in group 2 on the periodic table are called

1 answer:

Ludmilka [50]3 years ago

3 0

Answer:

group two elements are called alkaline earth metals

Explanation:

Because their oxides form in the earth and are water soluble

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How many electrons can the px atomic orbital subtype hold?

NemiM [27]

The p sublevel holds 6 electrons because it has 3 orbitals.

8 0

3 years ago

Mass=1.01 kg; volume =1000cm3

guajiro [1.7K]

Density = 1.01 g/cm^3 or 1.01 kg/dm^3 or 1010 kg/m^3

Density = mass/volume = 1010 g/1000 cm^3 = 1.01 g/cm^3 = 1.01 kg/dm^3

= 1010 kg/m^3

7 0

3 years ago

For the balanced equation shown below, if the reaction of 0.112 grams of

Alekssandra [29.7K]

Answer:

The answer is 74.5%.

Explanation:

As we know that % yield= $\frac{actual yield}{theoretical yield}$ x 100%.

Therefore,

Step 1 Calculate Theoretical yield:

0.112 $H_{2}$ x $\frac{1 mol H_{2} }{2.016 g of H{2} }$ x $\frac{4 mol H_{2}O }{4 mol H_{2} }$ x $\frac{18.02 g H_{2}O }{1 mol H_{2}O}$ = 1.001 g $H_{2}O$

Now Step 2

% yield = $\frac{actual yield}{theoretical yield}$ x 100% = $\frac{0.745g}{1.001g}$ = 74.5%

8 0

3 years ago

If 5.12 g of oxygen O2 gas occupies a volume of 6.21L at a certain temperature and pressure, how many grams of oxygen gas will o

ddd [48]

Answer : The mass of $O_2$ occupy 30.3 L under the same conditions will be, 24.9 grams.

Explanation :

First we have to calculate the moles of $O_2$

$\text{Moles of }O_2=\frac{\text{Given mass }O_2}{\text{Molar mass }O_2}=\frac{5.12g}{32g/mol}=0.16mol$

Now we have to calculate the moles of $O_2$ in 30.3 L by using Avogadro's law.

Avogadro's law : It is defined as the volume of gas is directly proportional to the number of moles of gas at constant pressure and temperature.

$V\propto n$

or,

$\frac{V_1}{n_1}=\frac{V_2}{n_2}$

where,

$V_1$ = initial volume of gas = 6.21 L

$V_2$ = final volume of gas = 30.3 L

$n_1$ = initial moles of gas = 0.16 mol

$n_2$ = final temperature of gas = ?

Now put all the given values in the above equation, we get:

$\frac{6.21L}{0.16mol}=\frac{30.3L}{n_2}$

$n_2=0.781mol$

Now we have to calculate the mass of $O_2$

$\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2$

Molar mass of $O_2$ = 32 g/mol

$\text{ Mass of }O_2=(0.781moles)\times (32g/mole)=24.9g$

Therefore, the mass of $O_2$ occupy 30.3 L under the same conditions will be, 24.9 grams.

6 0

3 years ago

The continental crust is _________ than the oceanic crust and seems to "float" on the mantle.

zavuch27 [327]

The continental crust is less dense than the <span>oceanic crust and seems to "float" on the mantle.</span>

4 0

3 years ago