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3 years ago

Bond energy:

Chemistry

1 answer:

lianna [129]3 years ago

4 0

Answer:

Hi how are you doing today Jasmine

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What volume of DI water, in mL, must you use to dissolve 30.0 g of NaOH in order to make a 1.25 M solution? mL (round to whole n

jeka57 [31]

Answer:

600mL

Explanation:

Molarity of a solution (M) = number of moles (n) ÷ volume (V)

number of moles = mass/molar mass

Molar mass of NaOH = 23 + 16 + 1

= 40g/mol

mole = 30/40

n of NaOH = 0.75mol

Using Molarity = n/V

V = number of moles ÷ molarity

V = 0.75 ÷ 1.25

V = 0.6L

In milliliters (mL), the volume of NaOH will be 0.6 × 1000

= 600mL

4 0

3 years ago

What is the weight of a 30.0 kg object? 3.0 N 300 N 6.8 N 132 N

andreyandreev [35.5K]

Explanation:

$w \: = mg \\ = 30\:kg \times 10\:ms^{-2}\\=300\:kg\:ms^{-2} \\ = 300\:N$

6 0

3 years ago

Read 2 more answers

What does it mean Emphasis on object vs woman

GenaCL600 [577]

Emphasis on object vs woman simply means s- e- x- ual objectification

This goes to say that it emphasizes seeing women as objects of se- xu- al pleasure

<h3>What is objectification?</h3>

Objectification simply refers to the act of treating or viewing a person as an object, devoid of thought or feeling.

Most of the time, objectification is targeted at women and reduces them to objects of se- xu- al pleasure

So therefore, emphasis on object vs woman simply means se- xu- al objectification

Learn more about se- xu- al objectification:

brainly.com/question/4231708

#SPJ1

6 0

2 years ago

What is the name of the compound PbS2 • 4H2O?

Ainat [17]

Should be :

Lead Sulfate Tetrahydrate

6 0

3 years ago

Cyclopropane, a substance used with oxygen as a general anesthetic, contains only two elements, carbon and hydrogen. When 1.00 g

ELEN [110]

Answer:

CH₂

Explanation:

From the question given above, the following data were obtained:

Mass of compound = 1 g

Mass of CO₂ = 3.14 g

Mass of H₂O = 1.29 g

Empirical formula =?

Next, we shall determine the mass of Carbon and hydrogen present in the compound. This can be obtained as follow:

For Carbon, C:

Mass of CO₂ = 3.14 g

Molar mass of CO₂ = 12 + (2×16)

= 12 + 32

= 44 g/mol

Molar mass of C = 12 g/mol

Mass of C =?

Mass of C = molar mass of C/ Molar mass of CO₂ × Mass of CO₂

Mass of C = 12/44 × 3.14

Mass of C = 0.86 g

For hydrogen, H:

Mass of C = 0.86 g

Mass of compound = 1 g

Mass of H =?

Mass of H = (Mass of compound) – (mass of C)

Mass of H = 1 – 0.86

Mass of H = 0.14 g

Finally, we shall determine the empirical formula of the cyclopropane. This can be obtained as follow:

Mass of C = 0.86 g

Mass of H = 0.14 g

Divide by their molar mass

C = 0.86 / 12 = 0.07

H = 0.14 / 1 = 0.14

Divide by the smallest

C = 0.07 / 0.07 = 1

H = 0.14 / 0.07 = 2

Thus, the empirical formula of cyclopropane is CH₂

8 0

3 years ago