2 years ago

Pada setiap tumbukan berlaku hukum

Physics

1 answer:

sweet-ann [11.9K]2 years ago

6 0

Hij ane les spoona sudhea alldor oakie

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The critical angle for a certain air-liquid surface is 47.7°. What is the index of refraction of the liquid? Round to the neares

KengaRu [80]

Answer:

The index of refraction of the liquid is 1.35.

Explanation:

It is given that,

Critical angle for a certain air-liquid surface, $\theta_1=47.7^{\circ}$

Let n₁ is the refractive index of liquid and n₂ is the refractive index of air, n₂ =1

Using Snell's law for air liquid interface as :

$n_1\ sin\theta_1=n_2\ sin(90)$

$n_1\ sin(47.7)=1$

$n_1=\dfrac{1}{sin(47.7)}$

$n_1=1.35$

So, the index of refraction of the liquid is 1.35. Hence, this is the required solution.

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3 years ago

What color is seen when the red light is on

Dennis_Churaev [7]

Answer:

Red is seen

Explanation:

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3 years ago

A ball rolls onto the path of your car as you drive down a quiet neighborhood street. to avoid hitting the child that runs to re

KengaRu [80]

Since the acceleration of car is uniform so the distance traveled by car while brakes are applied is given by

$d = \frac{v_f + v_i}{2}*t$

given that

$v_f = 9 m/s$

$v_i = 15 m/s$

$t = 1.20 s$

now plug in all data in above formula

$d = \frac{15 + 9}{2} * 1.2$

$d = 14.4 m$

so car will cover 14.4 m distance while it apply brakes

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3 years ago

What is the magnetic field strength required to make a proton with a speed of 5.0 x 10^(5) m/s follow a circular path of radius

Nuetrik [128]

Answer:

Magnetic field strength required for this is 0.25 T

Explanation:

As we know that the proton moves in circular path in uniform magnetic field

so the radius of the path of the circle is given as

$R = \frac{mv}{qB}$

here we know that

$q = 1.6 \times 10^{-19}C$

$m = 1.6 \times 10^{-27} kg$

$R = 0.0200 m$

$v = 5 \times 10^5 m/s$

now we have

$B = \frac{1.6 \times 10^{-27} (5 \times 10^5)}{(1.6 \times 10^{-19})(0.02)}$

so we have

$B = 0.25 T$

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3 years ago

who described atoms as having a positive nucleus with electrons that have different energies at different distances from the nuc

zysi [14]

Answer to your question : Niels Bohr

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3 years ago