Answer:
The force required to begin to lift the pole from the end 'A' is 240 N
Explanation:
The given parameters for the pole AB are;
The length of the pole, l = 10.0 m
The weight of the pole, W = 600 N ↓
The distance of the center of gravity of the pole from the side 'A' = 4.0 m
Let '
' represent the force required to begin to lift the pole from the end 'A' and let a force applied in the upwards direction be positive
For equilibrium, the sum of moment about the point 'B' = 0, therefore, taking moment about 'B', we have
× 10.0 m - W × 4.0 m = 0
∴ × 10.0 m = W × 4.0 m = 600 N × 4.0 m
× 10.0 m = 600 N × 4.0 m
∴ = 600 N × 4.0 m/(10.0 m) = 240 N
The force required to begin to lift the pole from the end 'A', = 240 N.
Answer:
Ok, so the car has traversed a total of 2 + 4 + 2 + 6 = 14 miles.
That's the car's distance! :)
For the displacement, you can draw out a diagram. I'll try my best to make one using a keyboard xDDD
- - - - |
| |
| - - - start - end!
So, this is the journey of the car: Going two up, 4 left, 2 down, and 6 right.
This ends up 2 to the right of the beginning!
That's a 2 mile displacement :)
Can you give me brainliest for my splendid diagram? xD
The prime meridian passes through Greenwich, England. That also touches the north and South Pole, making a half circle. It’s the Prime Meridian
