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Tamiku [17]
3 years ago
14

Solve for y. Solve for z. x + y + z = 4 4x - y - z = 1 x + z = 2

Mathematics
1 answer:
kaheart [24]3 years ago
8 0

Answer:

x = 1, y = 2, z = 1

Step-by-step explanation:

Adding the first 2 equations to each other gives

x + y + z + 4x - y - z = 4 + 1

which simplifies to

5x = 5, so x = 1

x + z = 2 so 1 + z = 2, so z = 1 too

x + y + z = 4 = 1 + y + 1 = 2 + y so y = 2

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Which expression is equivalent to (5^3)^9/5^12.PLEASE HELP IMMEDIATELY
Trava [24]

Answer:

(5³)⁹/5¹² = 1

Step-by-step explanation:

(5³)⁹/5¹²

Add the exponents

5¹²/5¹²

Divide

1

3 0
3 years ago
F(x)=-3/5x+k and if f(30)=-11 what is the value of k
Kruka [31]

Answer:

k=20.

Explanation: First we find where f(x) has its local extrema: f'(x)=3x2−10x+3. The critical points are roots of the equation: 3x2−10x+3=0.

6 0
3 years ago
GIVING BRAINLIEST Use the inequality 186< -3 (4x - 2).
a_sh-v [17]

Answer:

x < -15

Step-by-step explanation:

I solved the inequality but i don't know if that was what you were asking for lol, if not sorry.

3 0
3 years ago
HELP ILL AWARD BRAINLIEST
inna [77]

Answer:

Think about it

Step-by-step explanation:

If you made $20 in 2 hrs you made $10 per hour

To find out how much you make per certain number of hrs multiply $10 by the number of hours

The equation is y = 10x + 0 <-- this is also answer to number 4

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5 0
4 years ago
Read 2 more answers
which inequality represents all values of x for which the quotient below is defined?√8x^2 divided by √2x
MA_775_DIABLO [31]

Answer:

The function is defined when x > 0

Step-by-step explanation:

Functions with radicals are only undefined when the value in the radical is negative, because the root of a negative number is imaginary.  

We know the function is undefined when the denominator is equal to zero.  \sqrt{2x} is equal to zero when x=0.

We also know that functions with radicals are undefined when the value in the radicals are negative, because the root of a negative number is imaginary.  .  8x^{2} will always be positive, but 2x is negative when x < 0.

So the function is undefined when x = 0, and when x < 0.

Therefore it is defined when x > 0

5 0
3 years ago
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