The maximum allowable torque must correspond to the allowable shear stress for maximization. To solve this, we use the torsion formula:
Max. Allowable Shear Stress = Maximum Torque ÷ Cross-Sectional Area
8 x 10^6 Pa = Maximum Torque ÷ pi*(d/2)²
Maximum Torque = 8 x 10^6 Pa * pi*(0.06/2)² m²
Maximum Torque = 22,619.47 J or
Maximum Torque = 22.62 kJ
As for the second question, I have no reference figure so I am unable to answer it. I hope I was still able to help you, though.
Explanation:
The force on the passenger will be F = ma
Here, m does not change, but a is the variable.
If the cars slows down very fast, the acceleration will be higher, and thus the force will be higher.
If the acceleration is lower, the force will be lower as well, which would be the most desirable scenario for the passenger.
Determined the displacement of a plane is 66 m:s
<span>If
a contour interval of a topographic map is 50 feet, there would be 3
contour lines drawn between sea level and an elevation of 175 feet.</span>
The type of heat that the Sun emits is called UV (Ultra Violet) rays. This is a natural type of heat, but it can also be dangerous if you expose yourself to too much UV heat, causing "sunburns", or even skin cancer.
