The speed of the water in the wider part will be 1.194 m/sec. Speed is a time-based quantity. Its SI unit is m/sec.
<h3> What is speed?</h3>
Speed is defined as the rate of change of the distance or the height attained.
The given data in the problem is;
The initial diameter is,
initial radius,

The initial crossection area;

The final crossection area;

The initial flow rate is;
R = density ×velocity ×area

The speed of the water in the wider part will be;
From the continuity equation;

Hence, the speed of the water in the wider part will be 1.194 m/sec.
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<h2>
Answer:</h2>
800gm
<h2>
Explanation:</h2>
Archimedes principle states that when an object is immersed in a liquid there is an apparent loss of weight of the object. This apparent loss of weight is also the upthrust experienced by the liquid. The upthrust is equal to the weight of the liquid displaced.
Following from the above statement, when the body of volume 100c.c is immersed in the water contained in the jar, the upthrust experienced is equal to the weight of the water displaced.
<em>Note: In the question, weight is measured just using the mass.</em>
Mass (m) is the product of density (ρ) of liquid (which is water in this case) and volume (v) of body immersed. i.e
m = ρ x v
Where;
ρ = 1 gm/cm³
v = 100c.c = 100cm³
=> m = 1 gm/cm³ x 100cm³
=> m = 100gm
Therefore the weight of water displaced is 100gm
Now, the weight of the water and jar after immersion is the sum of the weight of water and jar before immersion, and the weight of the water displaced. i.e
Weight of water and jar after immersion = 700gm + 100gm = 800gm
Answer:
(A) –14m/s
(B) –42.0m
Explanation:
The complete solution can be found in the attachment below.
This involves the knowledge of motion under the action of gravity.
Check below for the full solution to the problem.
Down stream it would be going 20 mph and up stream 10 mph
The period T of a pendulum is given by:

where L is the length of the pendulum while

is the gravitational acceleration.
In the pendulum of the problem, one complete vibration takes exactly 0.200 s, this means its period is

. Using this data, we can solve the previous formula to find L: