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ser-zykov [4K]
3 years ago
13

Winding a chain A 30-m-long chain hangs vertically from a cylinder attached to a winch. Assume there is no friction in the syste

m and the chain has a density of 5 kg/m. How much work is required to wind the entire chain onto the cylinder using the winch
Physics
1 answer:
Tcecarenko [31]3 years ago
5 0

Answer:

Explanation:

Assuming that velocities remain negligible,

The work will be equal to the change in potential energy of the center of mass

mass is 30 m(5 kg/m) = 150 kg

W = 150(9.8)(30/2) = 22,050 J ≈ 22 kJ

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A car starts from rest with an acceleration of 8 m/s/s for a time of 4 s. What was the car's final velocity?
Aleks [24]
32m/s
8m/s x 4s= 32m/s
6 0
3 years ago
Red light of wavelength 630 nm passes through two slits and then onto a screen that is 1.4 m from the slits. The center of the 3
VARVARA [1.3K]

Answer:

Part a)

f = 4.76 \times 10^{14} Hz

Part b)

d = 3.48 \times 10^{-4} m

Part c)

\theta = 0.311 degree

Explanation:

Part a)

As we know that the speed of light is given as

c = 3 \times 10^8 m/s

\lambda = 630 nm

now the frequency of the light is given as

f = \frac{c}{\lambda}

so we have

f = \frac{3 \times 10^8}{630 \times 10^{-9}}

f = 4.76 \times 10^{14} Hz

Part b)

Position of Nth maximum intensity on the screen is given as

y_n = \frac{n\lambda L}{d}

so here we know for 3rd order maximum intensity

y_3 = 0.76 cm

n = 3

L = 1.4 m

0.76 \times 10^{-2} = \frac{3(630 \times 10^{-9})(1.4)}{d}

d = 3.48 \times 10^{-4} m

Part c)

angle of third order maximum is given as

d sin\theta = 3 \lambda

3.48 \times 10^{-4} sin\theta = 3(630 \times 10^{-9})

\theta = 0.311 degree

8 0
3 years ago
When light shines through atomic hydrogen gas, it is seen that the gas absorbs light readily at a wavelength of 91.63 nm. What i
Artist 52 [7]

Answer:

D) 21

Explanation:

When gas absorbs light , electron at lower level jumps to higher level .

and the difference of energy of orbital is equal to energy of radiation absorbed.

Here energy absorbed is equivalent to wavelength of 91.63 nm

In terms of its energy in eV , its energy content is eual to

1243.5 / 91.63 = 13.57 eV. This represents the difference the energy of orbit .

Electron is lying in lowest or first level ie n = 1.

Energy of first level

= - 13.6 / 1² = - 13.6 eV.

Energy of n th level = - 13.6 / n². Let in this level electron has been excited

Difference of energy

= 13.6 - 13.6 / n² = 13.57 ( energy of absorbed radiation)

13.6 / n² = 13.6 - 13.57 = .03

n² = 13.6 / .03 = 453

n = 21 ( approx )

4 0
3 years ago
Atomic theory describes the motion of particles in solids, liquids, and gases. Which statement best describes the particles in a
Alex787 [66]
B is the answer because a solid would not be able to hold its shape if it was able to move around
5 0
3 years ago
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What units should be used when measuring the mass of a ladybug?
Aleks [24]
You could use grams hope this helps
3 0
3 years ago
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