To solve this problem it is necessary to apply the concepts related to the Period of a body and the relationship between angular velocity and linear velocity.
The angular velocity as a function of the period is described as

Where,
Angular velocity
T = Period
At the same time the relationship between Angular velocity and linear velocity is described by the equation.

Where,
r = Radius
Our values are given as,


We also know that the radius of the earth (r) is approximately

Usando la ecuación de la velocidad angular entonces tenemos que



Then the linear velocity would be,

x

The speed would Earth's inhabitants who live at the equator go flying off Earth's surface is 463.96
No conclusive evidence exists on “average” 1-mile run times, because there is no scientifically agreed-upon average runner. Opinion varies widely, but most anecdotal evidence places the average between seven and 10 minutes per mile for a non-competitive, in-shape runner.
False because friction will generate heat energy and/or sound energy etc. Think of a car stopping or a broom sweeping the ground.
Answer:
h = 157.70 meters
Explanation:
Given the following data;
Mass = 5.5 kg
Gravitational potential energy = 8500 Joules
We know that acceleration due to gravity is equal to 9.8 m/s².
To find the height of the object;
Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.
Mathematically, gravitational potential energy is given by the formula;

Where;
G.P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
Substituting into the formula, we have;
8500 = 5.5*9.8*h
8500 = 53.9h
h = 8500/53.9
h = 157.70 m