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swat32
3 years ago
11

A 0.2 kg plastic cart and a 20 kg lead cart both roll without friction on a horizontal surface. Equal forces are used to push bo

th carts forward for a time of 1 s, starting from rest. Is the momentum of the plastic cart greater than, less than, or equal to the momentum of the lead cart?
Physics
1 answer:
garik1379 [7]3 years ago
8 0

Answer:

The same

Explanation:

The change in momentum of each cart is equal to the impulse given by the force applied on the cart:

\Delta p = I = F \Delta t

where

F is the force applied

\Delta t is the time during which the force is applied

The force applied to both carts (F) is the same, as well as the time (\Delta t). This means that the change in momentum, \Delta p, is the same for both carts. But both carts start from rest (momentum = 0): this means that at the end, both carts will have exactly same momentum.

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An object that has a small mass and an object that has a large mass have the same momentum. which object has the largest kinetic
castortr0y [4]
The larger mass object would have more kinetic energy. 1) its heavier 2) it covers a larger area 3) the more mass an object has, the larger the kinetic energy because of its weight.
6 0
3 years ago
A student rides a bicycle for 15 miles in 3 hours. What is the student's speed? What else would you need to know for the velocit
kaheart [24]

Answer:

5 miles per hour

Explanation:

if you divide 15 by 3 you get 5, therefore the student is going 5 miles per hour.

3 0
3 years ago
A 1.5 kg orange falls from a tree and hits the ground in 0.75s. What is the speed of the orange just before it hits the ground?
Olenka [21]

The final speed of the orange is 7.35 m/s

Explanation:

The motion of the orange is a free fall motion, since there is only the force of gravity acting on it. Therefore, it is a uniformly accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. So we can use the following suvat equation:

v=u+at

where

v is the  final velocity

u is the initial velocity

a is the acceleration

t is the time elapsed

For the orange in this problem, we have

u = 0 (it is dropped from rest)

a=g=9.8 m/s^2 is the acceleration

Substituting t = 0.75 s, we find the final velocity (and speed) of the orange:

v=0+(9.8)(0.75)=7.35 m/s

Learn more about free fall:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

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8 0
3 years ago
An athlete swings a ball, connected to the end of a chain, in a horizontal circle. The athlete is able to rotate the ball at the
Andrei [34K]

Answer:

a) 2nd case rate of rotation gives the greater speed for the ball

b) 1534.98 m/s^2

c) 1515.04 m/s^2

Explanation:

(a) v = ωR

when R = 0.60, ω = 8.05×2π

v = 0.60×8.05×2π = 30.34 m/s

Now in 2nd case

when R = 0.90, ω = 6.53×2π

v = 0.90×6.53×2π = 36.92 m/s

6.35 rev/s gives greater speed for the ball.

(b) a = ω^2 R = (8.05×2π)^2 )(0.60) = 1534.98 m/s^2

(c) a = ω^2 R = (6.53×2π)^2 )(0.90) = 1515.05 m/s^2

7 0
3 years ago
A car traveled north 25 km for 1 hour. The car’s SPEED is 25 km/hr north.
kramer

Answer:

hgk

Explanation:

6 0
3 years ago
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