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sukhopar [10]
3 years ago
12

Please help please help

Physics
1 answer:
Inessa [10]3 years ago
6 0

Answer: p= m/v so 90kg/.075m^3 = 1,200

2a. .35 m 1.1 m and .015 m

2b. 35 cm x 110 cm x 1.5 cm = 5,775 cm^3 = 57.75 m^3

mass= pv

2700•57.75= 155,925 kg

mass= 155,925 kg

volume= 57.75 m^3

Explanation: physics

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Fynjy0 [20]
B. gas has no definite shape or volume. liquid has definite volume but no definite shape
4 0
3 years ago
If planet i is 30.3 million miles farther from the sun than planet​ ii, then planet iii is 24.6 million miles farther from the s
kkurt [141]
Since the total distance for all three of the planets is 196.2 million miles, you would add planet i and planet iii, then subtract that number from 196.2

planet i and planet iii equaled 54.9 million miles, that subtracted from 196.2 equals 141.3

So your answer is 141.3 million miles
3 0
3 years ago
The area of the large cylinder's piston in this hydraulic system is 3.14 m2. What is the output force?
Black_prince [1.1K]

The output force is

<em>F = (input force) x (3.14) / (area of the </em><u><em>small</em></u><em> cylinder's piston)</em>

4 0
3 years ago
A solid-propellant rocket has chamber pressure of 6.35 atm with propellant density of 3.8 g/cm3 and burn area of 975 cm2 . Find
cupoosta [38]

Answer:

Explanation:

Given:

P = 6.35 atm

= 1.01 × 10^5 × 6.35

= 6.434 × 10^5 N/m^2

As = 975 cm^2

D = 3.8 g/cm^2

M = 320 kg

Since the propellant volume is equal to the cross sectional area, As times the fuel length, the volumetric propellant consumption rate is the cross section area times the linear burn rate, bs , and the instantaneous mass flow rate of combustion, ms gases generated is equal to the volumetric rate times the fuel density, D

ms = D × As × bs

ms ÷ bs = M/L

M/L = 3.8 × 975

= 3705 g/cm

= 3.705 × 10^6 kg/m^3

Pressure = mass × g/area

= mass/length × time^2

t = sqrt(3.705 × 10^6/6.43 × 10^5)

= 2.4 s

4 0
3 years ago
Please helppppppppppppp
artcher [175]

The ball's initial velocity must be 28.0 m/s

Explanation:

The motion of the ball in this problem is a projectile motion, so it follows a parabolic path, consisting of two separate motions:  

- A uniform motion (constant velocity) along the horizontal direction  

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction  

First, we study the vertical motion of the ball: since it is a uniformly accelerated motion, we can use the suvat equation  to find the time it takes for the ball to reach the ground,

s=ut+\frac{1}{2}at^2  

where  

s = 40 m is the vertical displacement, the height of the cliff (we chose downward as positive direction)  

u = 0 is the initial vertical velocity of the ball

t is the time of flight of the ball

a=g=9.8 m/s^2 is the acceleration of gravity  

Solving for t, we find:

t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(40)}{9.8}}=2.86 s  

Now we can analyze the horizontal motion: since this is a uniform motion, the horizontal speed is constant, and it is given by

v_x = \frac{d}{t}

where:

d = 80 m is the horizontal distance covered by the ball

t = 2.86 s is the time of flight

Substituting,

v_x = \frac{80}{2.86}=28.0 m/s

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

4 0
3 years ago
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