There are 1.48 × 10²⁵ molecules of zinc oxide in a 2 kg sample. Details about number of molecules can be found below.
<h3>How to calculate number of molecules?</h3>
The number of molecules of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.
According to this question, there are 2000g of ZnO in a sample. Zinc oxide has a molar mass of 81.38 g/mol.
no of moles = 2000g ÷ 81.38g/mol
no of moles = 24.57mol
number of molecules = 24.57 × 6.02 × 10²³
number of molecules = 147.95 × 10²³
Therefore, there are 1.48 × 10²⁵ molecules of zinc oxide in a 2 kg sample.
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Answer:
10.56L
Explanation:
The following were obtained from the question given :
P1 = 845mmHg
V1 = 4.6L
P2 = 368mmHg
V2 =?
We can calculate the new volume by using Boyle's law as follows;
P1V1 = P2V2
845 x 4.6 = 368 x V2
Divide both side by 368
V2 = (845 x 4.6) / 368
V2 = 10.56L
Answer:
CaC₂(s) + 2H₂O(l) --> C₂H₂(g) + Ca(OH)₂(aq)
Explanation:
We are given;
The unbalanced equation;
CaC₂(s) + 2H₂O(l) --> C₂H₂(g) + Ca(OH)₂(aq)
We are required to balance the equation;
- We need to know that balancing of chemical equations involves putting the appropriate coefficients on reactants and products to ensure equal number of atoms of each element on both sides of the equation.
- Balancing of chemical equations is a try and error method of making sure that the law of conversation of mass in chemical equations is obeyed.
- In our case, the appropriate coefficients will be, 1, 2, 1, 1
Therefore;
The balanced equation will be;
CaC₂(s) + 2H₂O(l) --> C₂H₂(g) + Ca(OH)₂(aq)
