Always remember that a compound can be separated into simpler substances by chemical methods/reactions. While elements cannot be broken down into simpler substances by chemical reactions. You can do a flame test and spectrum analysis to determine whether a solid material is an element or a compound. Check the boiling and/or melting point, color or density. Also check the solid material’s reaction with oxygen, hydrogen, calcium, or various acids. Examine and study its physical chemistry. The element(s) that may be present may be identified by checking the absorption edges from an x-ray spectrum.
Answer:
When the solution turns clear, either at the end of the reaction or when you add sufficient cyclohexene
Explanation:
The colour of bromine in the solution is usually yellow, however when the solution turns clear, this shows that all the bromine has been consumed.
Another way to make sure that all the bromine molecules are consumed is by addition of an unsaturated hydrocarbon like cyclohexene. Cyclohexene will consume the bromine molecules and the solution will become clear, while the cyclohexene becomes more saturated by becoming bromo cyclohexane.
Answer:
a. Disminuye.
b. Disminuye.
Explanation:
¡Hola!
En este caso, considerando que tenemos una reacción en la cual se podría asumir que tanto la concentración de monóxido de carbono y la de oxígeno contribuye a la velocidad de reacción, de acuerdo a la siguiente cinética elemental:
![r=k[CO]^2[O_2]](https://tex.z-dn.net/?f=r%3Dk%5BCO%5D%5E2%5BO_2%5D)
Al aplicar los siguientes cambios, resultaría:
a. En este caso, bien sabemos que la velocidad de reacción es aumentada al adicionar un catalizador ya que la constante de velocidad aumenta al disminuir la energía de activación; no obstante, al retirar el catalizador, la energía de activación aumentaría y por consiguiente la velocidad de reacción disminuiría.
b. En este caso, dado que la relación entre el oxígeno y la rapidez de reacción es directamente proporcional, es possible para nosotros determinar que al eliminar parte del oxígeno, la concentración disminuye y por ende la velocidad de reacción también.
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the Empirical formula of the compound is calculated as follows
find the moles of each element
moles = mass/molar mass
that is Magnesium= 0.564 g /24 g/mol = 0.0235 moles
For oxygen = 0.376 g /16 g/mol= 0.0235 moles
find the mole ratio by dividing both moles of by 0.0235 moles
magnesium = 0.0235/0.0235= 1mole
oxygen= 0.0235 /0.0235= 1mole
therefore the empirical formula = MgO
Answer:
it is a point at which a liquid Start's to evaporate
Explanation:
the point at which a liquid turns to gass
