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3 years ago

PLEASE HELP

Chemistry

2 answers:

Ipatiy [6.2K]3 years ago

6 0

Your answer should be “C.”

MARK ME BRAINLIEST PLEASE!!!!!!

dsp733 years ago

6 0

Answer:

The answer is C.

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Calculate the grams of so2 gas present at stp in a 5. 9 l container. (atomic weights: s=32, o=16).

Solnce55 [7]

The 5.9 L container at STP contains 16.83 g of SO2.

To begin, we must determine how many moles of SO2 are contained in the 5.9 L container.

At standard temperature and pressure (STP), one mole of SO2 equates to 22.4 liters.

5.9 L = 5.9 / 22.45.9 L = 0.26 moles of SO2 as a result.

The result is that 0.263 moles of SO2 are present in the container.

Following that, we shall determine the mass of 0.263 moles of SO2.

The following are ways to do this:

The mass of SO2 is 32 + (16 2) = 32 + 32= 64 g/mol,

where SO2 Mole = 0.263 Molar.

Molar + Molar Mass Equals Mass

SO2 mass is 16.83 g, or 0.263 of a kilogram.

Therefore, 16.83 g of SO2 are present in the 5.9 L container at STP.

to know more about mass, visit to:-

brainly.com/question/15959704

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8 0

1 year ago

A 500 ml aqueous solution of na3po4 was prepared using 82g of the solute. what is the molarity

liraira [26]

Answer:

1 M

Explanation:

The molarity of a solution, M, is a measure of the concentration of that solution and it refers to the number of moles of solute (mol) per liter (L) of solution. The molarity (M) can be calculated using the formula:

M = number of moles (n) /volume (V)

In this question, a 500 ml aqueous solution of Na3PO4 was prepared using 82g of the solute.

Molar mass of Na3PO4 = 23(3) + 15 + 16(4)

= 69 + 31 + 64

= 164g/mol

Mole = mass/molar mass

mole = 82/164

mole = 0.5 mol

Volume in Litres (L) = 500 ml ÷ 1000 = 0.500L

Therefore, Molarity (M) = 0.5/0.500

Molarity = 1 M or 1 mol/L

7 0

3 years ago

I need the answer for the first question 1.

sp2606 [1]

metal salt acid hydroyon and why cuz I guessed and I haven't t learned this yet and I need points

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3 years ago

What atomic or hybrid orbitals make up the sigma bond between Cl and F in chlorine trifluoride, ClF3

Umnica [9.8K]

Answer:

sp³d¹ hybridization

Explanation:

Given Cl as central element with three F substrates ...

The VSEPR structure indicates 5 hybrid orbitals that contain 2 diamagnetic orbitals (non-bonded e⁻-pairs) and 3 paramagnetic orbitals (single, non-paired electron for covalent bonding with fluorine) giving a trigonal bypyrimidal parent with a T-shaped geometry.

Valence bond theory predicts the following during bonding:

Cl:[Ne]3s²3p²p²p¹3d⁰

=> [Ne]3s²p²p¹p¹d¹

=> [Ne]3(sp³d)²(sp³d)²(sp³d)¹(sp³d)¹(sp³d)¹

giving 3 ( [Cl](sp³d) - [F]2p¹ ) sigma bonds and 2 non-bonded pairs on Cl.

Note the following images:

Non-bonded electron pairs are in plane of parent geometry and Fluorides covalently bonded to central element Chloride forming the T-shaped geometry.

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2 years ago

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svetoff [14.1K]

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2 years ago

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