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choli [55]
3 years ago
8

PLEASE HELP

Chemistry
2 answers:
Ipatiy [6.2K]3 years ago
6 0

Your answer should be “C.”

MARK ME BRAINLIEST PLEASE!!!!!!

dsp733 years ago
6 0

Answer:

The answer is C.

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A volume of 100 mL of 1.00 M HCl solution is titrated with 1.00 M NaOH solution. You added the following quantities of 1.00 M Na
s344n2d4d5 [400]

Answer:

a: before equivalence point

b: equivalence point

c: before equivalence point

d: after the eqivalence point

e: before equivalence point

f:  after the eqivalence point

Explanation:

Balanced equation of reaction:

NaOH +HCl =NaCl +H2O;

Volume of HCl is fixed and it 100ml and concentration is 1.0M

N1 and N2 normality of HCl and NaOH respectively;

V1 and V2 volume of HCl and NaOH respectively;

we have given molarity but we need normality;

Normality=molarity \times n-factor

<em>but in case of NaOH and HCl n-factor is 1 for each.</em>

hence

normality=molarity;

At equivalence point:  N_1V_1=N_2V_2

Before equivalence point : N_1V_1>N_2V_2

After the equivalence point: N_1V_1

N_1V_1=100\times1=100

case a:  5.00 mL of 1.00 M NaOH

N_2V_2=5\times1=5

N_1V_1>N_2V_2 hence it is before equivalence point

case b: 100mL of 1.00 M NaOH

N_2V_2=100\times1=100

N_1V_1=N_2V_2 hence it is equivalence point

case c:  10.0 mL of 1.00 M NaOH

N_2V_2=10\times1=10

N_1V_1>N_2V_2 hence it is before equivalence point

case d: 150 mL of 1.00 M NaOH

N_2V_2=150\times1=150

N_1V_1 hence it is after the eqivalence point

case e: 50.0 mL of 1.00 M NaOH

N_2V_2=50\times1=50

N_1V_1>N_2V_2 hence it is before equivalence point

case f: 200 mL of 1.00 M NaOH

N_2V_2=200\times1=200

N_1V_1 hence it is after the eqivalence point

7 0
3 years ago
In an experiment, two unknown compounds (one an alcohol and the other an ether) of equal molecular mass were dissolved in water.
-BARSIC- [3]

Answer: B. It is an ether because it is unable to to form a hydrogen bond, so it is less soluble than water

Explanation: Alcohols (ROH) are more soluble in water as they can form hydrogen bonding with water whereas ethers (ROR) are less soluble as they do not form hydrogen bonds with water.

For formation of hydrogen bond, the electronegative atom (F, Oand N) must be attached to hydrogen and in ethers (ROR), there is no hydrogen directly attached to electronegative oxygen atom, thus are less soluble in water.


4 0
3 years ago
Write the charge and full ground-state electron configuration of the monatomic ion most likely to be formed by each:
Sladkaya [172]

Answer:

Part A:

Charge is P^{3-}

Configuration is 1s^2 2s^22p^63s^23p^6

Part B:

Charge is Mg^{2+}

Configuration is 1s^2 2s^22p^6

Part C:

Charge is Se^{2-}

Configuration is 1s^2 2s^22p^63s^23p^64s^23d^{10}4p^6

Explanation:

Monatomic ions:

These ions consist of only one atom. If they have more than one atom then they are poly atomic ions.

Examples of Mono Atomic ions: Na^+, Cl^-, Ca^2^+

Part A:

For P:

Phosphorous (P) has 15 electrons so it require 3 more electrons to stabilize itself.

Charge is P^{3-}

Full ground-state electron configuration of the mono atomic ion:

1s^2 2s^22p^63s^23p^6

Part B:

For Mg:

Magnesium (Mg) has 12 electrons so it requires 2 electrons to lose to achieve stable configuration.

Charge is Mg^{2+}

Full ground-state electron configuration of the mono atomic ion:

1s^2 2s^22p^6

Part C:

For Se:

Selenium (Se) has 34 electrons and requires two electrons to be stable.

Charge is Se^{2-}

Full ground-state electron configuration of the mono atomic ion:

1s^2 2s^22p^63s^23p^64s^23d^{10}4p^6

8 0
3 years ago
4. A sign in a town gives the speed limit at 50.00 km/hr. What is this speed in cm/sec?​
ivanzaharov [21]

sorry but if you are looking for an answer I don't know one. :(

3 0
2 years ago
If expending 3500 kcal is equal to a loss of 1.0 lb, how many days will it take Charles to lose 5.0 lb? Express your answer to t
Trava [24]

Answer:

WAIT

good luck on whatever this is for my dude.

3 0
2 years ago
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