Step-by-step explanation:
1/sin^2A -cos^2A/sin^2 A. ~tan = sin/cos
(1-cos^2)/sin^2A. ~ take lcm
sin^2A/sin^ A. ~ 1-cos^2A = sin^2A
1
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with that template in mind, let's see

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.
Algebraically, that would be 5n - 11 = 24
Answer:
f(3) = 10
Step-by-step explanation:
If x = 3 then fill in the x's on the original equation and solve;
f(x) = 2x + 4
f(3) = 2(3) + 4
2 x 3 = 6
6 + 4 = 10
So, f(3) = 10
Hope this helps!!!