Answer:
fdg
Step-by-step explanation:
One can solve this by first using order of operations, and then combining like terms.
First is parenthesis
9x + 2x(9) - 2(9x)
Now we do the multiplication
9x + 18x - 18x
Now we combine like terms
9x
Answer:
1. D. 20, 30, and 50
2. A. 86
3. B. 94
Step-by-step explanation:
1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.
The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.
Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.
Thus:
Q1 = (85 + 87)/2 = 86
Q3 = (93 + 95)/2 = 94
IQR = Q3 - Q1 = 94 - 86
IQR = 8
Outliers in the data set are data values below the lower limit or above the upper limit.
Let's find the lower and upper limit.
Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74
The data values below the lower limit (74) are 20, 30, and 50
Let's see if we have any data value above the upper limit.
Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106
No data value is above 106.
Therefore, the only outliers of the data set are:
D. 20, 30, and 50
2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.
Thus:
Q1 = (85 + 87)/2 = 86
3. Q3 = (93 + 95)/2 = 94
For the first 3 you just have to divide (forget about the square root for now) and then reduce its result by finding two numbers (one of them have to be able to be squared rotted) that multiplied gives the fist result. Then you just have to square root one of the numbers and leave the other one as it is.
For the last 4; you cannot have radicals in the denominator, so you have to multiply both top and bottom by the square root, after that you just reduce.
Hope you understand, if you have any questions please let me know.
Answer:
18 units
Step-by-step explanation:
If you draw lines from the corner points (L, E, J, and P) to the center, you will find that they bisect the corner angles. For the lines to be tangent, LU=LK, PU=PV, JV=JS, and ES=EK.
Perimeter=LK+KE+ES+SJ+JV+VP+PU+UL
Since LU=LK=4, PU=PV=1, JV=JS=2, and ES=EK=2
Perimeter=4+2+2+2+2+1+1+4
Perimeter=18
