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attashe74 [19]
3 years ago
8

a beaker with water and the surrounding air are all at degrees Celsius. After ice cubes are placed in the water, heat is transfe

rred from?
Chemistry
2 answers:
Yuki888 [10]3 years ago
8 0

(3) the water to the ice cubes
  This is so because the ice cubes are colder compared to their surrounding objects.
They absorb the heat from the water, cooling it, therefore vanishing(melting).

Another way to put it would be

The answer is (3) the water to ice cubes.

As the ice cubes should be at a temperature of about 0 degree ( freezing point) , at the same time the temperature of water is 24 degree. Thus, heat is transferred from water to ice cubes.

AfilCa [17]3 years ago
4 0

Answer:

(3) the water to the ice cubes.

Explanation:

There is some info missing. I believe this is the original question:

<em>A beaker with water and the surrounding air are all at 24°C. After ice cubes are placed in the water, heat is transferred from:(1) the ice cubes to the air(2) the beaker to the air(3) the water to the ice cubes(4) the water to the beaker.</em>

<em />

Heat is transferred from bodies at higher temperatures to bodies at lower temperatures.

<em>Heat is transferred from:</em>

<em>(1) the ice cubes to the air.</em> NO. Heat will be transferred from air (24°C) to the ice cubes (0°C).

<em>(2) the beaker to the air.</em> NO. The beaker and the air are at the same temperature.

<em>(3) the water to the ice cubes.</em> YES. Water (24°C) is at a higher temperature than ice (0°C).

<em>(4) the water to the beaker.</em> NO. The water and the beaker are at the same temperature.

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3 0
3 years ago
What volume of oxygen (in L) is produced
sveticcg [70]

Answer:

12.36 L.

Explanation:

We'll begin by calculating the number of mole in 147.1 g of lead(II) nitrate, Pb(NO₃)₂. This can be obtained as follow:

Molar mass of Pb(NO₃)₂ = 207.2 + 2[14.01 + (16×3)]

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Mass of Pb(NO₃)₂ = 147.1 g

Mole of Pb(NO₃)₂ =?

Mole = mass / Molar mass

Mole of Pb(NO₃)₂ = 147.1 / 331.22

Mole of Pb(NO₃)₂ = 1.104 moles.

Next, we shall determine the number of mole of oxygen gas, O₂, produce from the reaction. This can be obtained as follow:

2Pb(NO₃)₂ —> 2PbO + 4NO₂ + O₂

From the balanced equation above,

2 moles of Pb(NO₃)₂ decomposed to produce 1 mole of O₂.

Therefore, 1.104 moles of Pb(NO₃)₂ will decompose to produce = (1.104 × 1)/2 = 0.552 mole of O₂.

Finally, we shall determine the volume occupied by 0.552 mole of oxygen gas, O₂. This can be obtained as follow:

1 mole of O₂ occupied 22.4 L at STP.

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