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attashe74 [19]
3 years ago
8

a beaker with water and the surrounding air are all at degrees Celsius. After ice cubes are placed in the water, heat is transfe

rred from?
Chemistry
2 answers:
Yuki888 [10]3 years ago
8 0

(3) the water to the ice cubes
  This is so because the ice cubes are colder compared to their surrounding objects.
They absorb the heat from the water, cooling it, therefore vanishing(melting).

Another way to put it would be

The answer is (3) the water to ice cubes.

As the ice cubes should be at a temperature of about 0 degree ( freezing point) , at the same time the temperature of water is 24 degree. Thus, heat is transferred from water to ice cubes.

AfilCa [17]3 years ago
4 0

Answer:

(3) the water to the ice cubes.

Explanation:

There is some info missing. I believe this is the original question:

<em>A beaker with water and the surrounding air are all at 24°C. After ice cubes are placed in the water, heat is transferred from:(1) the ice cubes to the air(2) the beaker to the air(3) the water to the ice cubes(4) the water to the beaker.</em>

<em />

Heat is transferred from bodies at higher temperatures to bodies at lower temperatures.

<em>Heat is transferred from:</em>

<em>(1) the ice cubes to the air.</em> NO. Heat will be transferred from air (24°C) to the ice cubes (0°C).

<em>(2) the beaker to the air.</em> NO. The beaker and the air are at the same temperature.

<em>(3) the water to the ice cubes.</em> YES. Water (24°C) is at a higher temperature than ice (0°C).

<em>(4) the water to the beaker.</em> NO. The water and the beaker are at the same temperature.

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Answer:

m = 32.34 pounds of ice.

Explanation:

In this case we need to use the following expression of heat:

q = m * ΔHf   (1)

Where:

q: heat absorbed in J or kJ

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ΔHf: heat of fusion of the water in kJ/g

We are asked to look for the mass of ice in pounds, so after we get the grams, we need to convert the grams to pounds, using the following conversion:

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So, we have the heat and heat of fusion, from (1) let's solve for the mass, and then, using (2) the conversion to pounds:

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Now, the conversion to pounds:

m = 14,670.66 g * 1 pound/453.59 g

<h2>m = 32.34 pounds of ice.</h2>

Hope this helps  

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