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nika2105 [10]
3 years ago
8

What is the mass of 30.0 ml of a solution with a density of 1.60 g/ml?

Chemistry
2 answers:
mel-nik [20]3 years ago
7 0

Answer:

The correct answer is mass = 48g

Explanation:

Hello!

Let's solve this!

The data is:

volume: 30.0 ml

density: 1.60 g / ml

The density formula is:

density = mass / volume

From this formula we cleared the mass:

mass = density * volume

mass = (1.6g / ml) * 30ml = 48g

We conclude that the correct answer is mass = 48g

irinina [24]3 years ago
5 0
The answer is 48g
30 x 1.60 = 48
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B). light energy is not required to proceed

Explanation:

In the Calvin cycle of photosynthesis, light energy is not required. The Calvin cycle is light independent and it is made up of a series of redox reactions.

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  • During the Calvin cycle aspect, light energy is not required for chemical reactions to take place. The light energy helps to move electrons.
  • The cycle is also known as dark reactions.
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Be sure to answer all parts. Consider the reaction A + B → Products From the following data obtained at a certain temperature, d
worty [1.4K]

Answer : The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

The overall order of reaction is, first order reaction.  

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

A+B\rightarrow Products

Rate law expression for the reaction:

\text{Rate}=k[A]^a[B]^b

where,

a = order with respect to A

b = order with respect to B

Expression for rate law for first observation:

3.20\times 10^{-1}=k(1.50)^a(1.50)^b ....(1)

Expression for rate law for second observation:

3.20\times 10^{-1}=k(1.50)^a(2.50)^b ....(2)

Expression for rate law for third observation:

6.40\times 10^{-1}=k(3.00)^a(1.50)^b ....(3)

Dividing 1 from 2, we get:

\frac{3.20\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k(1.50)^a(2.50)^b}{k(1.50)^a(1.50)^b}\\\\1=1.66^b\\b=0

Dividing 1 from 3, we get:

\frac{6.40\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k(3.00)^a(1.50)^b}{k(1.50)^a(1.50)^b}\\\\2=2^a\\a=1

Thus, the rate law becomes:

\text{Rate}=k[A]^1[B]^0

\text{Rate}=k[A]

Thus,

The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

The overall order of reaction is, first order reaction.

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