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beks73 [17]
3 years ago
14

Which scientist was the first to conclude through experimentation that atoms contain most of their mass in a small, dense nucleu

s?
Chemistry
1 answer:
AURORKA [14]3 years ago
4 0

Answer:

Ernest Rutherford

Explanation:

Ernest Rutherford was the first to conclude experiments

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Magnesium chloride is an important coagulant used in the preparation of tofu from soy milk. Its solubility in water at 200C is 5
Gennadij [26K]

Answer:

(a) Homogeneous. 4.7 g of MgCl₂.

(b) 9.1 g

Explanation:

(a)

At 200°C, we can dissolve 54.6g of MgCl₂ in 100 g of water. The mass that we could dissolve in 38.2 g of water is:

38.2gWater.\frac{54.6gMgCl_{2}}{100gWater} =20.9g

Since we can dissolve up to 20.9 g of MgCl₂ and we added only 16.2 g, the mixture is homogeneous and we could add 20.9 g -16.2 g = 4.7 g of solute to make it saturated.

(b)

At 800°C, we can dissolve 66.1 g of MgCl₂ in 100 g of water. The mass that we could dissolve in 38.2 g of water is:

38.2gWater.\frac{66.1gMgCl_{2}}{100gWater} =25.3g

Since we can dissolve up to 25.3 g of MgCl₂ and we added only 16.2 g, we could add 25.3 g - 16.2 g = 9.1 g of solute to make it saturated.

7 0
3 years ago
Please help I’m really stuck:/
iris [78.8K]

Answer:

i would say two

Explanation:

I did the math

6 0
3 years ago
If the temperature changes by 100 K, by how much does it change in °C?
m_a_m_a [10]
The temperature changes by <span>#-173 ^(o) C#</span>
5 0
4 years ago
Read 2 more answers
An electrochemical cell is constructed using electrodes with the following half-cell reactions.
marshall27 [118]

Answer:

E cell = +1.95 V

Explanation:

At Anode : Oxidation reaction takes place

At Cathode : Reduction reaction takes place

The reaction with lower value of reduction potential will undergo Oxidation

Mn^{2+}(aq)+2e^{-}\rightarrow Mn(s)   E = -1.18 V

This equation undergo oxidation reaction and become:

Anode(Oxidation-Half) :

Mn(s)\rightarrow Mn^{2+}(aq)+2e^{-}      E = +1.18 V

Cathode(Reduction-Half) :

Fe^{3+}(aq)+e^{-}\rightarrow Fe^{2+}    E =+0.77 V

To balance the reaction multiply reduction-Half with 2.We get :

Fe^{3+} +2Mn(s)+\rightarrow Fe^{2+} + 2Mn^{2+}

Note that E is intensive property , do not multiply E  of oxidation-half with 2

Ecell =  0.77 -(-1.18)

E = +1.95 V

3 0
3 years ago
Inches of mercury (inHg) is commonly used as unit of atmospheric pressure. It indicates the height of Hg (in inch) that atmosphe
777dan777 [17]

Answer:

The answer to your question is 0.92 atm

Explanation:

Data

Atmospheric pressure = 27.6 inHg

Atmospheric pressure = ? atm

Process

1.- Convert inHg to cmHg

                      1 in Hg ------------------- 2.54 cm

                    27.6 inHg ----------------- x

                     x = (27.6x 2.54) / 1

                     x = 70.1 cm

2.- Convert cmHg to mmHg

                     2.54 cm ----------------- 25.4 mmHg

                      70.1 cm ----------------  x

                      x = (70.1 x 25.4)/2.54

                      x = 701 mmHg

3.- Convert mmHg to atm

                      760 mmHg ------------- 1 atm

                      701 mmHg  -------------  x

                       x = (701 x 1)/760

                       x = 0.922 atm

3 0
4 years ago
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