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3 years ago

14

Which scientist was the first to conclude through experimentation that atoms contain most of their mass in a small, dense nucleu

s?

1 answer:

AURORKA [14]3 years ago

4 0

Answer:

Ernest Rutherford

Explanation:

Ernest Rutherford was the first to conclude experiments

You might be interested in

How many atoms of carbon are represented in 3CH3CH20

pishuonlain [190]

6 carbon atoms

          H H
         | |
3 x   H - C - C - O - H
   | |
      H H

8 0

3 years ago

The metals in Groups 1A, 2A, and 3A ____.

Ket [755]

The correct answer is D.

I hope that helped! c:

6 0

4 years ago

Which of the following is false? a. an apoenzyme can catalyze its reaction without its cofactor b an organic cofactor can be cal

ozzi

Answer: Option (a) is the correct answer.

Explanation:

A protein part of an enzyme is known as an apoenzyme. An apoenzyme combines with a cofactor, it is known as holoenzyme.

Without a cofactor an apoenzyme cannot function as cofactor helps in the formation of an active enzyme system and provides a specific site on enzyme for the substrate.

Whereas a non-protein chemical compound or metal ion that helps in the activity of enzyme as a catalyst is known as a cofactor. A metal ion cofactor can be bound directly to the enzyme or to a coenzyme.

The organic non-protein molecules which bind to the protein molecule to form an active enzyme is known as a coenzyme. Coenzymes are small size molecules which help the enzymes to act as a catalyst.

Therefore, we can conclude that the statement an apoenzyme can catalyze its reaction without its cofactor, is false.

3 0

4 years ago

Aqueous sulfuric acid (H2SO4) reacts with solid sodium hydroxide (NaOH) to produce aqeous sodium sulfate (Na2SO4) and liquid wat

Montano1993 [528]

Answer:

The theoretical yield of water formed is 2.2 grams

Explanation:

Step 1: Data given

Mass of H2SO4 = 5.9 grams

Mass of NaOH = 6.6 grams

Molar mass H2SO4 = 98.08 g/mol

Molar mass of NaOH = 40.0 g/mol

Step 2: The balanced equation

2NaOH + H2SO4 → Na2SO4 + 2H2O

Step 3: Calculate moles

Moles = mass / molar mass

Moles H2SO4 = 5.9 grams / 98.08 g/mol

Moles H2SO4 = 0.060 moles

Moles NaOH = 6.6 grams / 40.0 g/mol

Moles NaOH = 0.165 moles

Step 4: Calculate the limiting reactant

For 2 moles NaOH we need 1 mol H2SO4 to produce 1 mol Na2SO4 and 2 moles H2O

H2SO4 is the limiting reactant. It will completely be consumed ( 0.060 moles). NaOH is in excess . There will react 2*0.060 = 0.120 moles

There will remain 0.165 - 0.120 = 0.045 moles NaOH

Step 5: Calculate moles H2O

For 2 moles NaOH we need 1 mol H2SO4 to produce 1 mol Na2SO4 and 2 moles H2O

For 0.0600 moles H2SO4 we'll have 2*0.0600 = 0.120 moles H2O

Step 6: Calculate mass H2O

Mass H2O = 0.120 moles * 18.02 g/mol

Mass H2O = 2.16 grams

The theoretical yield of water formed is 2.2 grams

4 0

3 years ago

Assuming tea leaves contain 5.0% caffeine by weight what is the maximum weight of caffeine you could isolate from 10.g of tea le

Fiesta28 [93]

Answer:

0.50 g Caffeine

Explanation:

Step 1: Given data

Concentration of caffeine by weight in tea leaves: 5.0%

Mass of tea leaves: 10. g

Step 2: Calculate the maximum weight of caffeine that can be isolated

The concentration of caffeine by weight in tea leaves is 5.0%, that is, there are 5.0 g of caffeine per 100 g of tea leaves. The maximum weight of caffeine in 10. g of tea leaves is:

10. g Tea leaves × 5.0 g Caffeine/100 g Tea leaves = 0.50 g Caffeine

7 0

3 years ago