Answer : The molal freezing point depression constant of X is 
Explanation : Given,
Mass of urea (solute) = 5.90 g
Mass of X liquid (solvent) = 450.0 g
Molar mass of urea = 60 g/mole
Formula used :
where,
= change in freezing point
= freezing point of solution = 
= freezing point of liquid X= 
i = Van't Hoff factor = 1 (for non-electrolyte)
= molal freezing point depression constant of X = ?
m = molality
Now put all the given values in this formula, we get
![[0.4-(-0.5)]^oC=1\times k_f\times \frac{5.90g\times 1000}{60g/mol\times 450.0g}](https://tex.z-dn.net/?f=%5B0.4-%28-0.5%29%5D%5EoC%3D1%5Ctimes%20k_f%5Ctimes%20%5Cfrac%7B5.90g%5Ctimes%201000%7D%7B60g%2Fmol%5Ctimes%20450.0g%7D)
Therefore, the molal freezing point depression constant of X is
Answer:
1- Option (A)
2- Option (A)
Explanation:
The pressure is often defined as the force per unit area. In the atmosphere, the pressure is maximum at the troposphere and is tightly packed near the ground surface. The troposphere is the region where the temperature decreases with the increasing height. The atmospheric pressure at sea level is nearly 1013.2 millibar (mb). The difference in the pressure in this layer causes the wind that is responsible for the occurrence of different types of weather patterns.
The earth and the sun maintains the shortest distance at its Perihelion position, which takes place in the month of January during the winter season in the northern hemisphere. And on the other hand, the earth is far away from the sun at its Aphelion position that takes place in the month of July.
Hence, the correct answers are given above.
I’m pretty sure the immediate answer is 2. Using the equation 60N=(30kg)x2(whatever unit of measure) also it will change because if you change the mass or the Net Force, your going to have to redo the equation based on the new information.
Answer :
Example of polar covalent molecules H-O-H(water), ammonia
Explanation:
The presence of intermolecular Hydrogen bonding makes the boiling point of water unexpectedly high, and the polar covalent nature makes it dissolve polar solute/compound
