The chemical formula of water is written as H2O we can just use the ratio of the atoms since we are not given the reaction. Hydrogen is a diatomic substance so that it exists as H2. We calculate as follows:
0.253 mol H2O ( 1 mol H2 / 1 mol H2O ) = 0.253 H2 needed
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Answer
1. 1cm=10mm, 1kg=1000g and 12in=1 ft
2. 50mm=5cm
48 in =4ft
36ft=12 yd
2.5m=250cm
1000mL= 1 L
Explanation
if 1cm=10mm then 5cm=?
5×10=50mm
if 12 in =1ft then 48in=?
48/12 =4 ft
if 1m=100cm, then 2.5m=?
2.5×100= 250cm
and when know from capacity that 1000mL is equivalent to 1 liter.
The molarity of a solution is defined as the moles of solute dissolved per kilogram of solvent. Therefore, we first compute the moles of KOH using:
Moles = mass / Mr
Moles = 23 / 56
Moles = 0.41
The volume of solvent is 1.6 liters
The density is 1 gram/cm³ = 1 kg/L
Mass of solvent = density * volume
Mass of solvent = 1 * 1.6
Mass of solvent = 1.6 kg
Molality = moles / kilogram
Molarity = 0.41 / 1.6
Molarity = 0.26
The molality of the solution is 0.26 molal.
Answer:
Explanation:
Mass of one tablet = 20 mg
Mass of two tablets = 
Percent that is soluble in water = 40%
Mass of tablet that is soluble in water = 
So, mass of solute is 
Density of water = 1 kg/L
Volume of water = 1 L
So, mass of 1 L of water is 
PPM is given by
Hence, the concentration of iodine in the treated water .
Constant variable/control variable
