Answer:
The concentration of the diluted solution is 3.75 M
Explanation:
Step 1: Data given
Volume of a stock solution = 75 mL = 0.075 L
The molarity of stock solution = 5.0 M
We add 25 mL, The total volume is 100 mL = 0.100 L
Step 2: Calculate the concentration of the diluted solution
C1*V1 = C2*V2
⇒with C1 = the initial concentration = 5.0 M
⇒with V1 = the initial volume = 0.075 L
⇒with C2 = the new concentration = TO BE DETERMINED
⇒with V2 = the diluted volume = 0.100 L
5.0 M * 0.075 L = C2 * 0.100L
C2 = (5.0M * 0.075 L) / 0.100 L
C2 = 3.75 M
The concentration of the diluted solution is 3.75 M
OD IS THE ANSWER
JDBDBDBDBDBSBSBSHSHSBBSBSBSB
1.) Carbon Dioxide.
2.) Sulfur Trioxide.
3.) Dinitrogen trioxide.
4.) Dinitrogen pentoxide.
5.) Phosphorus trichloride.
6.) Ammonia.
7.) Sulfur Hexachloride.
8.) Phosphorus Pentoxide.
9.) Carbon Tetrachloride.
10.) Silicon Dioxide.
11.) Carbon Disulfide.
12.) Phosphorus tribromide.
13.) I don't have notes on this one so I don't know.
14.) Aluminum Oxide.
15.) Dichloride Heptoxide. (Not 100% sure if that was a 2 or a 7 at the end.)
<em>Hope this helps and sorry it took so long I had to search through my chemistry notes from awhile ago. But I tried as best I could. :)</em>