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vesna_86 [32]
3 years ago
13

How do particles differ after a physical change?

Chemistry
1 answer:
KonstantinChe [14]3 years ago
3 0

Answer:

They are still the same particals just. packed together diffrently depending on what stae of matter it's in.

Explanation:

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A 1.25 g sample of aluminum is reacted with 3.28 g of copper (II) sulfate. What is the limiting reactant?
KengaRu [80]

Answer:

d. Copper (II) sulfate

Explanation:

Given data:

Mass of Al = 1.25 g

Mass of CuSO₄ = 3.28 g

What is limiting reactant = ?

Solution:

Chemical equation:

2Al + 3CuSO₄   →   Al₂ (SO₄)₃ + 3Cu

Number of moles of Al:

Number of moles = mass/molar mass

Number of moles = 1.25 g/ 27 g/mol

Number of moles = 0.05 mol

Number of moles of CuSO₄:

Number of moles = mass/molar mass

Number of moles = 3.28 g/ 159.6 g/mol

Number of moles = 0.02 mol

now we will compare the moles of reactant with product.

               Al           :           Al₂ (SO₄)₃

                 2          :             1

               0.05       :          1/2×0.05=0.025 mol

                Al           :            Cu

                 2            :              3

               0.05         :            3/2×0.05 = 0.075 mol

         CuSO₄           :           Al₂ (SO₄)₃

                3             :             1

               0.02         :          1/3×0.02=0.007 mol

         CuSO₄           :            Cu

               3               :              3

               0.02         :              0.02

Less number of moles of reactants are produced by CuSO₄ thus it will act as limiting reactant.

4 0
3 years ago
N2 + 3 H2 → 2 NH3
sweet [91]

Answer:

B

Explanation:

5 0
3 years ago
What does the symbol Cp
xenn [34]

Answer:

From what i've learned so far, the correct answer is "Heat at a constant Pressure" or "Specific Heat"

Explanation:

Hope this helps!

8 0
3 years ago
arrange the following in order of increasing mass . a. 16 water molecules b. 2 atoms of lead 3. 5.1*10^-23​
Lesechka [4]
The answer is b i just took the test
4 0
3 years ago
Consider this equilibrium reaction between carbon monoxide and hydrogen gas, occurring in a sealed flexible container. CO(g) + 3
wariber [46]

Answer:

More H2(g) is added to the container : <u>Towards products.</u>

CO is removed from the container : <u>Towards reactants.</u>

More CH4(g) is added to the container : <u>Towards reactants</u>

H2O(g) is removed from the container <u>: Towards products.</u>

The contents of the container are heated up. :<u> Towards the reactants.</u>

The contents of the container are cooled down : <u>Towards the products.</u>

The pressure inside the container is increased. :<u>Towards the products</u>

The container is stretched to increase the volume: <u>Towards the reactants.</u>

Explanation: :

CO(g) + 3 H2g) → CH4(g) + H2O(g)+ heat

There is released heat, so this reaction is exothermic

If the H2 concentration is increased, the system will try to change the concentration change by shifting the balance to the right, and thus the concentration of products will increase.<u> Towards products.</u>

If the CO is removed, the system will try to change this situation by shifting the balance to the left, and thus the concentration of reactants will increase, the concentration of products will decrease. <u>Towards reactants.</u>

If the CH4 concentration is increased, the system will try to change the concentration change by shifting the balance to the left, and thus the concentration of reactants will increase. <u>Towards reactants</u>

If the H2O is removed, the system will try to change this situation by shifting the balance to the right, and thus the concentration of products will increase, the concentration of products will decrease. <u>Towards products.</u>

If the temperature is increased, the system will reduce the amount of heat released. So the balance will shift to the left. <u>Towards the reactants.</u>

This because the extra heat / energy must be used.

If the temperature is decreased, the system will produce more heat  So the balance will shift to the right. <u>Towards the products.</u>

This because more heat /energy needs to be produced to make up for the loss of heat (energy).

If the pressure is increased, the system will shift to the side with fewer moles of gas. In this case, there are 4 moles on the left and 2 moles on the right.  So the balance will shift to the right. <u>Towards the products.</u> An increase of pressure has the same effect on the equilibrium as a decrease of the volume.

If the volume is increased, this means the pressure is decreased, the system will shift to the side with most moles of gas. In this case, there are 4 moles on the left and 2 moles on the right.  So the balance will shift to the left. <u>Towards the reactants.</u> An increase of volume has the same effect on the equilibrium as a decrease of the pressure.

6 0
3 years ago
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