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2 years ago

Solve x^2+3x+2=0 using the quadratic formula

Mathematics

1 answer:

zzz [600]2 years ago

8 0

Answer:

x=−1,−2

Step-by-step explanation:

thats the answer

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Suppose a rectangular pasture is to be constructed using 1 2 linear mile of fencing. The pasture will have one divider parallel

timama [110]

Answer:

$\displaystyle A=\frac{1}{192}$

Step-by-step explanation:

<u>Maximization With Derivatives</u>

Given a function of one variable A(x), we can find the maximum or minimum value of A by using the derivatives criterion. If A'(x)=0, then A has a probable maximum or minimum value.

We need to find a function for the area of the pasture. Let's assume the dimensions of the pasture are x and y, and one divider goes parallel to the sides named y, and two dividers go parallel to x.

The two divisions parallel to x have lengths y, thus the fencing will take 4x. The three dividers parallel to y have lengths x, thus the fencing will take 3y.

The amount of fence needed to enclose the external and the internal divisions is

$P=4x+3y$

We know the total fencing is 1/2 miles long, thus

$\displaystyle 4x+3y=\frac{1}{2}$

Solving for x

$\displaystyle x=\frac{\frac{1}{2}-3y}{4}$

The total area of the pasture is

$A=x.y$

Substituting x

$\displaystyle A=\frac{\frac{1}{2}-3y}{4}.y$

$\displaystyle A=\frac{\frac{1}{2}y-3y^2}{4}$

Differentiating with respect to y

$\displaystyle A'=\frac{\frac{1}{2}-6y}{4}$

Equate to 0

$\displaystyle \frac{\frac{1}{2}-6y}{4}=0$

Solving for y

$\displaystyle y=\frac{1}{12}$

And also

$\displaystyle x=\frac{\frac{1}{2}-3\cdot \frac{1}{12}}{4}=\frac{1}{16}$

Compute the second derivative

$\displaystyle A''=-\frac{3}{2}.$

Since it's always negative, the point is a maximum

Thus, the maximum area is

$\displaystyle A=\frac{1}{12}\cdot \frac{1}{16}=\frac{1}{192}$

6 0

2 years ago

The domain of the following relation: R: {(−3, 4), (5, 0), (1, 5), (2, 8), (5, 10)} is:

Shalnov [3]

Answer:

For an ordered pair (x,y) that a set contain :

x = Domain of the relation

y = Range of the relation

In a relation x can have two or more than two ranges i.e a x can have more or more than two images.

So, Domain = First element of ordered pair that the following relation R contains ={(−3, 4), (5, 0), (1, 5), (2, 8), (5, 10)}= -3, 5, 1,2,5

But the element 5 is Occuring twice.

Domain = { -3,1,2,5} →→Option A

3 0

2 years ago

Read 2 more answers

10 pts!!

meriva

G(x)=-3/7(2)x is the actual answer, I'm doing the same stuff

3 0

3 years ago

4 + 2x2(3x-5)<br> number of terms

igor_vitrenko [27]

3, assuming 2x2 is 2x squared, u will get
4 + 6x3 - 10x2

So 3 terms

7 0

2 years ago

Plz help I really need it and you get 15 points

Andrei [34K]

1. 1 x-200= -200
2. -200 x 1= -200
3. 2 x -100= -200
4. -100 x 2= -200
5. -20 x 10= -200
6. -10 x 20= -200
7. -40 x 5= -200
8. -5 x 40= -200
Hope this helps! :)

8 0

1 year ago