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statuscvo [17]
3 years ago
6

23. The force required to accelerate a 2.0-kilogram

Physics
1 answer:
Marianna [84]3 years ago
4 0
Answer:
C) 8.0 N

Explanation:
F=m*a
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Select the correct answer.
Natali5045456 [20]

(NH4)2CO3(s) ⇄ 2NH3(g) + CO2(g) + H2O (g)

The  effect  that adding  water (H2O)   have in reaction above is  that The  concentration of the product  would  decrease, and the concentration of reactant  would increase. (answer  C)


   <u><em>Explanation</em></u>

  •  If the  concentration   of one substance is changed, the equilibrium  shift to minimize  the effect of that change.
  • H2O   in reaction above  is  a product.

  • Increase of water (H2O)  concentration will led to the shift of equilibrium  to the left ( reactant  side)  .The concentration of  reactant  increase  as that of product decrease.
6 0
3 years ago
Upon being struck by 240-nm photons, a metal ejects electrons with a maximum kinetic energy of 2.97 eV. What is the work functio
Neko [114]

Answer:

Work Function = 3.53 x 10⁻¹⁹ J = 2.2 eV

Explanation:

The work function of the metal metal can be found as follows:

Energy of Photon = Work Function + K.E

hc/λ = Work Function + K.E

Work Function = hc/λ - K.E

where,

h = Plank's Constant = 6.625 x 10⁻³⁴ J.s

c = speed of light  = 3 x 10⁸ m/s

λ = wavelength of photons = 240 nm = 2.4 x 10⁻⁷ m

K.E = Maximum Kinetic Energy = (2.97 eV)(1.6 x 10⁻¹⁹ J/1 eV) =  4.752 x 10⁻¹⁹ J

Therefore,

Work Function = (6.625 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(2.4 x 10⁻⁷ m) - 4.752 x 10⁻¹⁹ J

Work Function = 8.281 x 10⁻¹⁹ J - 4.752 x 10⁻¹⁹ J

<u>Work Function = 3.53 x 10⁻¹⁹ J = 2.2 eV</u>

4 0
3 years ago
According to the exercise principle of balance, a workout should __________.
xxMikexx [17]
<span>a. address all components of fitness 

</span>According to the exercise principle of balance, a workout should address all components of fitness.
<span>NOT:
</span>b. focus on balance and coordination 
<span>c. target specific areas for improvement </span>
<span>d. vary exercise activities over time</span>

6 0
4 years ago
Read 2 more answers
Why don’t we feel the gravitational force of a large object such as a skyscraper semi-truck?
Kobotan [32]

Answer:

Se the explanation below

Explanation:

We do not feel these forces of these bodies, because they are very small compared to the force of Earth's attraction. Although its mass is greater than that of a human being, its mass is not compared to the Earth's mass. In order to understand this problem we will use numerical data and the universal gravitation formula, to give validity to the explanation.

<u>Force exerted by the Earth on a human being</u>

<u />

F=G*\frac{m_{1}*m_{2}}{r^2}

Where:

G = universal gravitation constant = 6.673*10^-11 [N*m^2/kg^2]

m1 = mass of the person = 80 [kg]

m2 = mass of the earth 5.97*10^24[kg]

r = distance from the center of the earth to the surface or earth radius = 6371 *10^3 [m]

<u />

Now replacing we have

F = 6.673*10^{-11} *\frac{80*5.97*10^{24}}{(6371*10^{3})^{2}  } \\F = 785[N]

<u>Force exerted by a building on a human being</u>

<u />

Where:

G = universal gravitation constant = 6.673*10^-11 [N*m^2/kg^2]

m1 = mass of the person = 80 [kg]

m2 = mass of the earth 300000 [ton] = 300 *10^6[kg]

r = distance from the building to the person = 2[m]

F = 6.673*10^{-11}*\frac{80*300*10^6}{2^{2} }  \\F= 0.4 [N]

As we can see the force exerted by the Earth is 2000 times greater than that exerted by a building with the proposed data.

8 0
3 years ago
Jupiter nudges the asteroids through the influence of:.
strojnjashka [21]
Orbital resonances.

Hope this helps!
Please give Brainliest!
4 0
2 years ago
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