We have,
- The mass of sally's mug is 1 kg
- The pressure appliedby the mug is 1100 pascal.
We know that,
As, we already have the value of pressure, let's calculate that of force now;
- F = ma
- F = 1 × 9.8 { Acceleration due to gravity, let's round off it to 10}
- F = 10 N
Just put all the values in the formula now;
- P = F/A
- 1100 = 10 / A
- 1100/10 = A
- 110 m² = A
As, it is already mention that we need to find the radius of the mug, it is obviously a circular base.
We know that,
- Surface area = Circumference
So, let's solve it;
- Circumference = 2πr
- 110 = 2 × 22/7 × r
- 110 × 7/2 × 22 = r
- 5 × 7 = r
- 35 cm = r
<u>T</u><u>h</u><u>u</u><u>s</u><u>,</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>r</u><u>a</u><u>d</u><u>i</u><u>u</u><u>s</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>c</u><u>i</u><u>r</u><u>c</u><u>l</u><u>e</u><u> </u><u>i</u><u>s</u><u> </u><u>3</u><u>5</u><u> </u><u>c</u><u>m</u><u>.</u>
To keep cars safe...............
Answer:
Volume flow rate = 
Explanation:
The volume flow rate through a channel can be gotten by multiplying its area and its velocity.
The channel under consideration is a circular channel. Hence, the cross-sectional area can be calculated by using the relation for calculating the area of a circle
Cross-sectional area = 
volume flow rate= 
Volume flow rate =
In the exosphere, there is thin air, since it is the uppermost level in the atmosphere. It is made mostly of helium and hydrogen. But, traces of other gases such as atomic oxygen and carbon dioxide can also be found in the exosphere.
What’s the rest of the question or is that it?
