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KengaRu [80]
3 years ago
9

Which change will cause the greatest increase in the rate of reaction for this chemical reaction? 8Zn(s) + S8(s) 8ZnS(s) A. addi

ng a catalyst B. increasing the temperature C. increasing the surface area D. increasing the concentration
Chemistry
2 answers:
Rus_ich [418]3 years ago
8 0

I found another question like this. Someone answered "The best answer to this question is adding a catalyst. 

Adding a catalyst  will cause the greatest increase in the rate of reaction for this chemical reaction , 8Zn(s) + S8(s) 8ZnS(s).                                                         ---> adding a catalyst always affects the rate of a reaction."

Sedbober [7]3 years ago
3 0

Answer:  A. adding a catalyst

Explanation:  The given reaction is -

                               8Zn(s) + S8(s) → 8ZnS(s)

Catalyst is the substance which is used to increase the rate of reaction. Thus adding the catalyst will give the greatest increase the rate of reaction by following the path which would have less activation energy.

Increasing the temperature will do increase the rate of reaction as kinetic energy of the reactants increasing thereby increasing the number of collisions.

Increasing the surface area and increasing the concentration will also increase the rate of reaction but the greatest increase will be shown by the addition of the catalyst.

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prisoha [69]
The answer is 5.32 × 10²³ molecules

<span>Avogadro's number is the number of units (atoms, molecules) in 1 mole of substance:
</span>6.023 <span>× 10²³ units per 1 mole

We have 0.883 moles.
If 1 mole has </span>6.023 × 10²³ molecules, 0.883 moles will have x molecules:
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x = 6.023 × 10²³ molecules * 0.883 moles : 1 mole = 5.32 × 10²³ molecules
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3 years ago
14 km is how many centimeters?
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2 years ago
You have 100 mL of a solution of benzoic acid in water; the amount of benzoic acid in the solution is estimated to be about 0.30
dimaraw [331]

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0.00370 g

Explanation:

From the given information:

To determine the amount of acid remaining using the formula:\dfrac{(final \ mass \ of \ solute)_{water}}{(initial \ mass \ of \ solute )_{water}} = (\dfrac{v_2}{v_1+v_2\times k_d})^n

where;

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n = numbers of extractions = 4

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∴

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +20 \ ml \times 10})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +200 \ ml})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{1}{3})^4

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Irina-Kira [14]

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The rate determining step is step 1

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