Answer:
HF is the limiting reactant
Explanation:
The balanced equation for the reaction is given below:
SiO₂ + 4HF —> SiF₄ + 2H₂O
From the balanced equation above,
1 mole of SiO₂ reacted with 4 moles of HF.
Finally, we shall determine the limiting reactant. This can be obtained as illustrated below:
From the balanced equation above,
1 mole of SiO₂ reacted with 4 moles of HF.
Therefore, 7.5 moles of SiO₂ will react with = 7.5 × 4 = 30 moles of HF.
From the calculation made above, we can see clearly that it will take a higher amount (i.e 30 moles) of HF than what was given from the question (i.e 5 moles) to react completely with 7.5 moles of SiO₂.
Therefore, HF is the limiting reactant and SiO₂ is the excess reactant.
Water is made up of atoms bonded to form molecules, the chemical formula for water is H20, and 1 side has a positive charge, while the other has a negative one.
<h3>What is water?</h3>
Water is a fundamental molecule for life on the Earth due to its physico-chemical properties.
The water formula is H2O, which means that this molecule is composed of two atoms of Hydrogen and one atom of Oxygen.
In conclusion, Water is made up of atoms bonded to form molecules, the chemical formula for water is H20, and 1 side has a positive charge, while the other has a negative one.
Learn more on water properties here:
brainly.com/question/18681949
#SPJ1
Jasmine pushes an object a distance of 15 m at constant speed. It produces a 450J of work on the object. What strength Jasmine does it exert on the object?
Answer:
30J
Explanation:
Given parameters:
Distance moved = 15m
Work done = 450J
Unknown:
Strength Jasmine applied = ?
Solution:
The strength Jasmine applied or exerted on the object is the force of pull that cause the motion of the object and the distance it was moved.
Now;
Work done = Force x distance
So;
450 = Force x 15
Force = 
= 30J
Answer:
Energy
potential energy kinetic energy
chemical energy thermal energy
joules
Explanation:
chemical energy is a type of potential energy or stored energy. Heat is a kinetic energy and energy is measured in joules.
Explanation:
For the given reaction 
Now, expression for half-life of a second order reaction is as follows.
![t_{1/2} = \frac{1}{[A_{0}]k}](https://tex.z-dn.net/?f=t_%7B1%2F2%7D%20%3D%20%5Cfrac%7B1%7D%7B%5BA_%7B0%7D%5Dk%7D)
....... (1)
Second half life of this reaction will be 
. So, expression for this will be as follows.
= ![\frac{1}{k} [\frac{1}{[A]_{f}} - \frac{1}{[A_{0}]}]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bk%7D%20%5B%5Cfrac%7B1%7D%7B%5BA%5D_%7Bf%7D%7D%20-%20%5Cfrac%7B1%7D%7B%5BA_%7B0%7D%5D%7D%5D)
...(2)
where ![[A]_{f}](https://tex.z-dn.net/?f=%5BA%5D_%7Bf%7D)
is the final concentration that is, ![\frac{[A]_{0}}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BA%5D_%7B0%7D%7D%7B4%7D)
here and ![[A]_{i}](https://tex.z-dn.net/?f=%5BA%5D_%7Bi%7D)
is the initial concentration.
Hence, putting these values into equation (2) formula as follows.
= ![\frac{1}{k} [\frac{4}{[A]_{0}} - \frac{1}{[A_{0}]}]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bk%7D%20%5B%5Cfrac%7B4%7D%7B%5BA%5D_%7B0%7D%7D%20-%20%5Cfrac%7B1%7D%7B%5BA_%7B0%7D%5D%7D%5D)
= ![\frac{3}{[A_{0}]k}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B%5BA_%7B0%7D%5Dk%7D)
...... (3)
Now, dividing equation (3) by equation (1) as follows.
= ![\frac{3}{[A_{0}]k} \times [A_{0}]k](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B%5BA_%7B0%7D%5Dk%7D%20%5Ctimes%20%5BA_%7B0%7D%5Dk)
= 3
or, = 3 
Thus, we can conclude that one would expect the second half-life of this reaction to be three times the first half-life of this reaction.
