the evidence does not support the argument because it addresses the bookmobile than the library itself
65% of the coins flipped landed with heads facing up because 13 were faced up out of 20.
Divide:
13/20=0.65=65%
Hope this helped☺☺
Answer:
independent: day number; dependent: hours of daylight
d(t) = 12.133 +2.883sin(2π(t-80)/365.25)
1.79 fewer hours on Feb 10
Step-by-step explanation:
a) The independent variable is the day number of the year (t), and the dependent variable is daylight hours (d).
__
b) The average value of the sinusoidal function for daylight hours is given as 12 hours, 8 minutes, about 12.133 hours. The amplitude of the function is given as 2 hours 53 minutes, about 2.883 hours. Without too much error, we can assume the year length is 365.25 days, so that is the period of the function,
March 21 is day 80 of the year, so that will be the horizontal offset of the function. Putting these values into the form ...
d(t) = (average value) +(amplitude)sin(2π/(period)·(t -offset days))
d(t) = 12.133 +2.883sin(2π(t-80)/365.25)
__
c) d(41) = 10.34, so February 10 will have ...
12.13 -10.34 = 1.79
hours less daylight.
The first equation is x = -1
The second and third equations are no solution
The third equation is all rel numbers.
We can tell each one by solving them. In the first one, you get the following.
4 + x = -8x - 5 ----> Add 8x to both sides
4 + 9x = -5 ----> Subtract 4 from both sides
9x = -9 ----> Divide both sides by 9
x = -1
For the middle two, when you attempt to solve, you get untrue statements. This shows there are no solutions. See the example below.
7 + 2x = 2x - 7 ----> Subtract 2x from both sides
7 = -7 (UNTRUE)
And for the last one, each term cancels out, which shows that we have all real solutions.
-3x + 3 = 3( 1 - x) ----> Distribute the 3
-3x + 3 = 3 - 3x ----> Add 3x to both sides
3 = 3 (TRUE)
Answer:
The tangent vector for
is:

Step-by-step explanation:
The function to be used is 
The unit tangent vector is the gradient of
divided by its norm, that is:

Where
is the gradient operator, whose definition is:

The components of the gradient function of
are, respectively:
,
and 
For
:
,
and 
The norm of the gradient function of
is:
![\| \vec \nabla r(t) \| = \sqrt{8^{2}+0^{2}+ [6\cdot \cos (2\cdot t)]^{2}}](https://tex.z-dn.net/?f=%5C%7C%20%5Cvec%20%5Cnabla%20r%28t%29%20%5C%7C%20%3D%20%5Csqrt%7B8%5E%7B2%7D%2B0%5E%7B2%7D%2B%20%5B6%5Ccdot%20%5Ccos%20%282%5Ccdot%20t%29%5D%5E%7B2%7D%7D)

For
:

The tangent vector for
is:
