1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Verizon [17]
3 years ago
6

During a certain time interval, a constant force delivers an average power of 4 watts to an object. if the object has an average

speed of 2 meters per second and the force acts in the direction of motion of the object, what is the magnitude of the force f~ ?
Physics
2 answers:
bija089 [108]3 years ago
3 0
<span>Force = Work done / distance = 4Nm / 2m = 2N</span>
ivolga24 [154]3 years ago
3 0

Answer:

2 N

Explanation:

The average power is defined as:

P=\frac{W}{\Delta t}(1)

Here W is the work done and t is the time interval in which the work is done.

The average speed is the rate of change of the position with respect to time:

v=\frac{x}{\Delta t}\\\Delta t=\frac{x}{v}(2)

Replacing (2) in (1):

P=\frac{Wv}{x}\\x=\frac{Wv}{P}(3)

The work done by a force F acting on an object undergoing a distance x, is given by:

W=Fxcos\theta

the force acts in the direction of motion of the object, so the angle between then is zero and the cosine is equal to one:

x=\frac{W}{F}(4)

Equaling (3) and (4):

\frac{Wv}{P}=\frac{W}{F}\\F=\frac{P}{v}\\F=\frac{4W}{2\frac{m}{s}}\\F=2N

You might be interested in
Number of waves that pass a given point in one second
Studentka2010 [4]
<em>number of waves that pass a given point in one second is called <u>frequency..</u></em>
5 0
3 years ago
Rank the nonmetals in each set from most reactive (1) to least reactive (3).
aksik [14]
Plz help me get out of this school im so tired im begging anybody i would do anything

7 0
3 years ago
Read 2 more answers
Four football players are running down the field at the same speed. Player 1 weighs 180 lbs and is running toward the south goal
ANTONII [103]
Player 4 ..................
3 0
3 years ago
Read 2 more answers
A quarterback throws a football toward a receiver with an initial speed of 20 m/s at an angle of 30∘ above the horizontal. At th
lana66690 [7]

Answer:

a) In order to catch the ball at the level at which it is thrown in the direction of motion.

b)Speed of the receiver will be 7.52m/s

Explanation:

Calculating range,R= Vo^2Sin2theta/g

R= (20^2×Sin(2×30)/9.8 = 35.35m

Let receiver be(R-20) = 35.35-20= 15.35m

The horizontal component of the ball is:

Vox= Vocostheta= 20× cos30°

Vox= 17.32m/s

Time taken to coverR=35.35m with 17.32m/s will be:

t=R/Vox= 35.35/17.32

t= 2.04seconds

b)Speed required to cover 15.35m at 2.04seconds

Vxreciever= d/t = 15.35/2.04 = 7.52m/s

7 0
3 years ago
Read 2 more answers
A swimming pool is 50 ft wide and 100 ft long and its bottom is an inclined plane, the shallow end having a depth of 4 ft and th
Nina [5.8K]

Explanation:

We define force as the product of mass and acceleration.

F = ma

It means that the object has zero net force when it is in rest state or it when it has no acceleration. However in the case of liquids. just like the above mentioned case, the water is at rest but it is still exerting a pressure on the walls of the swimming pool. That pressure exerted by the liquids in their rest state is known as hydro static force.

Given Data:

Width of the pool = w = 50 ft

length of the pool = l= 100 ft

Depth of the shallow end = h(s) = 4 ft

Depth of the deep end = h(d) = 10 ft.

weight density = ρg = 62.5 lb/ft

Solution:

a) Force on a shallow end:

F = \frac{pgwh}{2} (2x_{1}+h)

F = \frac{(62.5)(50)(4)}{2}(2(0)+4)

F = 25000 lb

b) Force on deep end:

F = \frac{pgwh}{2} (2x_{1}+h)

F = \frac{(62.5)(50)(10)}{2} (2(0)+10)

F = 187500 lb

c) Force on one of the sides:

As it is mentioned in the question that the bottom of the swimming pool is an inclined plane so sum of the forces on the rectangular part and triangular part will give us the force on one of the sides of the pool.

1) Force on the Rectangular part:

F = \frac{pg(l.h)}{2}(2(x_{1} )+ h)

x_{1} = 0\\h_{s} = 4ft

F = \frac{(62.5)(100)(2)}{2}(2(0)+4)

F =25000lb

2) Force on the triangular part:

F = \frac{pg(l.h)}{6} (3x_{1} +2h)

here

h = h(d) - h(s)

h = 10-4

h = 6ft

x_{1} = 4ft\\

F = \frac{62.5 (100)(6)}{6} (3(4)+2(6))

F = 150000 lb

now add both of these forces,

F = 25000lb + 150000lb

F = 175000lb

d) Force on the bottom:

F = \frac{pgw\sqrt{l^{2} + ((h_{d}) - h(s)) } (h_{d}+h_{s})   }{2}

F = \frac{62.5(50)\sqrt{100^{2}(10-4) } (10+4) }{2}

F = 2187937.5 lb

7 0
3 years ago
Other questions:
  • A wedge with an inclination of angle θ rests next to a wall. A block of mass m is sliding down the plane. There is no friction b
    11·1 answer
  • As air rises, why do clouds form?
    8·1 answer
  • 27 degrees to kelvin, 20 dg to milligrams, and 3 to decimeters.
    12·1 answer
  • Tracy stands on a skateboard and tosses her backpack to her friend who is standing in front of her. Which best describes the acc
    13·1 answer
  • 22 POINTS!!PLEASE HELP
    7·1 answer
  • Solve the following system of equations by using either substitution or elimination.
    14·1 answer
  • If a plane is moving at a constant velocity what is happening to the acceleration?
    14·2 answers
  • Which would heat up faster cotton or plastic
    7·1 answer
  • Two blocks of masses 1.0 kg and 2.0 kg, respectively, are pushed by a constant applied force F across a horizontal frictionless
    8·1 answer
  • During a race, a sprinter accelerated 1.8 m/s 2 in 2.5 seconds.How many meters per second did the sprint increase with this amou
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!