Least dangerous i could be wrong but feeding it to racoons.
Answer:
Explanation:
As we know that
here we have
also we know
so we have
so the height above window is given as
The mass of the hoop is the only force which is computed by:F net = 2.8kg*9.81m/s^2 = 27.468 N
the slow masses that must be quicker are the pulley, ring, and the rolling sphere.
The mass correspondent of M the pulley is computed by torque τ = F*R = I*α = I*a/R F = M*a = I*a/R^2 --> M = I/R^2 = 21/2*m*R^2/R^2 = 1/2*m
The mass equal of the rolling sphere is computed by: the sphere revolves around the contact point with the table. So using the proposition of parallel axes, the moment of inertia of the sphere is I = 2/5*mR^2 for spin about the midpoint of mass + mR^2 for the distance of the axis of rotation from the center of mass of the sphere. I = 7/5*mR^2 M = 7/5*m
the acceleration is then a = F/m = 27.468/(2.8 + 1/2*2 + 7/5*4) = 27.468/9.4 = 2.922 m/s^2
Answer:
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The resultant of two forces of 7N and 3N acting at a right angle to one another is √58 N. Explanation: Let the magnitude of the force of 7N be denoted as “F₁” on the x-axis and the magnitude of the force of 3N be denoted as “F₂” on the y-axis.Oct 22, 2019
Explanation:
