1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kenny6666 [7]
3 years ago
11

How much is required to accelerate a 5kg mass at 20 m/s2

Physics
1 answer:
zhannawk [14.2K]3 years ago
5 0

use F = ma

F : force m : mass a : acceleration

so

f = 5kg * 20 m/s2 = 100 N

You might be interested in
A wave hits a wall as shown. As the wave interacts with a wall, which kind of wave interaction is shown? absorption diffraction
dangina [55]
The answer is reflection.

The drawing is simple but illustrates the concept beautifully.
8 0
3 years ago
Read 2 more answers
A load of 1 kW takes a current of 5 A from a 230 V supply. Calculate the power factor.
Pachacha [2.7K]

Answer:

Power factor = 0.87 (Approx)

Explanation:

Given:

Load = 1 Kw = 1000 watt

Current (I) = 5 A

Supply (V) = 230 V

Find:

Power factor.

Computation:

Power factor = watts / (V)(I)

Power factor = 1,000 / (230)(5)

Power factor = 1,000 / (1,150)

Power factor = 0.8695

Power factor = 0.87 (Approx)

6 0
3 years ago
Lakes
Nataliya [291]
I think is between A&B
I think I would answer B
6 0
3 years ago
Starting from rest, a 2.1x10^-4 kg flea springs straight upward. While the flea is pushing off from the ground, the ground exert
Rainbow [258]

Answer:

a) The flea's speed when it leaves the ground is v=1.88m/s

b) The flea move 18cm upward while it is pushing off

Explanation:

Hi

<u>Knwons</u>

Mass m=2.1\times 10^{-4} kg, Work W=3.7\times 10^{-4} J and Force F=0.41N

a) Here we are going to use W=\frac{1}{2} mv^{2}, so v=\sqrt{\frac{2W}{m} }= \sqrt{\frac{2(3.7\times 10^{-4} J)}{2.1\times 10^{-4} kg} }=1.88m/s

a) Here we are going to use W=mgh, so h=\frac{W}{mg}= \frac{3.7\times 10^{-4} J}{(2.1\times 10^{-4} kg)(9.8m/s^{2})} =0,1797m or 18cm approx.

7 0
3 years ago
A redecor travelling of 94 m/s s lows at a anstant
kotykmax [81]

Answer:

638 m.

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 94 m/s

Final velocity (v) = 22 m/s

Time (t) = 11 s

Distance (s) =?

We can obtain the distance travelled by using the following formula:

s = (u + v) t /2

s = (94 + 22) × 11 /2

s = 116 × 11 /2

s = 1276 /2

s = 638 m

Thus, the distance travelled is 638 m.

3 0
3 years ago
Other questions:
  • A parachutist of mass 100 kg falls from a height of 500 m. Under realistic conditions, she experiences air resistance. Based on
    8·2 answers
  • If the pressure in the oil is 3.75 atm at the front end, how long can the pipeline be so that the pressure at the far end is no
    6·1 answer
  • Samantha is 1.1 m tall on her eleventh birthday and 1.21 m tall on her twelfth birthday. By what factor has her height increased
    7·1 answer
  • When you normally drive the freeway between Sacramento and San Francisco at an average speed of 115 km/hr (71 mi/h ), the trip t
    14·1 answer
  • Is the refractive index constant?
    9·2 answers
  • A Carnot heat engine uses a hot reservoir consisting of a large amount of boiling water and a cold reservoir consisting of a lar
    11·1 answer
  • Could an<br> average star, such as our<br> sun, become a neutron star?<br> Explain your answer.
    6·1 answer
  • 5. Describe the shape of the waveform in the secondary coil for a sine, square and triangle wave in the primary coil. How does t
    15·1 answer
  • Question 3 of 10
    8·2 answers
  • What is kinematics ???<br>need a legendary answer -,-" <br>xD ​
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!