We know that
applying the law of sines
a/sin A=b/sin B---------> a*sin B=b*sin A
<span>A = 80°, a = 24, b = 50
sin B=[b*sin A]/a-----> sin B=50*sin 80/24-----> sin B=2.0517
the sines value </span><span>can not be greater than 1
hence
the answer is
zero triangles</span>
Given:
The side of a square a, s+3.
The perimeter of a square is the sum of the four sides of the square. Hence,
Answer:
145°
Step-by-step explanation:
See the attachment. Angles A, B, and C all belong to the triangle.
We know that A + B + C = 180° since the angles of a triangle always add to 180°. We also know that when two lines meet that their sum is also equal to 180°. So we can write for each interior angle the following:
<u> Result</u>
<A = (180 - 88) 72
<B = (180-x) 180-x
<C = (180 - 127) 53
The sum of angles A, B, and C is equal to 180:
72 + (180-x) + 53 = 180
<h2><u>
x = 145</u></h2>
Answer:
Correct choice is B
Step-by-step explanation:
For the numbers -1 and 59, find the difference 59-(-1):
since 59-(-1)=60 and (two arithmetic means tells you there will be three intervals), two arithmetic means will be
The only correct sequence is -1, 19, 39, 59.
Answer: yes
Step-by-step explanation: