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3 years ago

I REALLY NEED HELP!!

Physics

1 answer:

Levart [38]3 years ago

4 0

Answer:

Explanation:

Although we do have an equation for this in terms of one-dimensional motion, it's easy enough just to use the mathematical definition of acceleration:

$a=\frac{v_f-v_0}{t}$ which says, in words, the acceleration of an object is equal to the objects final velocity minus its initial velocity, divided by the change in time. Since everything is given in m and s, our answer will be in m/s/s:

$a=\frac{16.0-4.0}{4.0}$ and

$a=\frac{12.0}{4.0}$ so

a = 3.0 m/s/s

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A 0.10-kg cart traveling in the positive x direction at 10.0 m/s collides with a 0.30-kg cart at rest. the collision is elastic.

yuradex [85]

By definition for an elastic shock, we have that if the second particle is at rest, then the final velocity of the first particle will be given by vf1 = ((m1-m2) * vi1) / (m1 + m2). Then, substituting the values: vf1 = ((0.1-0.3) * 10) / (0.1 + 0.4) = - 5m / s.

8 0

3 years ago

Read 2 more answers

A skier (m=59.0 kg) starts sliding down from the top of a ski jump with negligible friction and takes off horizontally. If h = 3

marissa [1.9K]

Answer:

35.20 m

Explanation:

By the law of conservation of energy we have,

$mg(H-h)=\frac{1}{2}mv^2$

$g(H-h)=\frac{1}{2}v^2$

$\Rightarrow H=\frac{v^2}{2g}+h$

where m= mass of the skier, h= 3.00 m

D= horizontal distance=13.9 m

H= maximum height attained

Also, the horizontal distance covered by the skier is

D=vt

$=v\frac{2g}{h}$

$\Rightarrow v^2=\frac{gD^2}{2h}$

thus, height H in terms of D is given by

$H=\frac{D^2}{2h}+h$

$H=\frac{13.9^2}{2\times3}+3$

H=35.20 m

4 0

3 years ago

An ideal monatomic gas initially has a temperature of T and a pressure of p. It is to expand from volume V1 to volume V2. If the

yawa3891 [41]

Answer:

Isothermal : P2 = ( P1V1 / V2 ) , work-done $pdv = nRT * In( \frac{V2}{v1} )$

Adiabatic : : P2 = $\frac{P1V1^{\frac{5}{3} } }{V2^{\frac{5}{3} } }$ , work-done =

W = $(3/2)nR(T1V1^(2/3)/(V2^(2/3)) - T1)$

Explanation:

initial temperature : T

Pressure : P

initial volume : V1

Final volume : V2

A) If expansion was isothermal calculate final pressure and work-done

we use the gas laws

= PIVI = P2V2

Hence : P2 = ( P1V1 / V2 )

work-done :

$pdv = nRT * In( \frac{V2}{v1} )$

B) If the expansion was Adiabatic show the Final pressure and work-done

final pressure

$P1V1^y = P2V2^y$

where y = 5/3

hence : P2 = $\frac{P1V1^{\frac{5}{3} } }{V2^{\frac{5}{3} } }$

Work-done

W = $(3/2)nR(T1V1^(2/3)/(V2^(2/3)) - T1)$

Where $T2 = T1V1^(2/3)/V2^(2/3)$

3 0

3 years ago

PLS HELP FOR PHYSICS PLS

Mumz [18]

Answer:

Chinese app which is number

Explanation:

7 0

3 years ago

HELP WILL MEDAL !!! if you give a inpproper statement you will be repoted

ehidna [41]

1: Weather has a somewhat unpredictable pattern.
2: They can misinterpret the pattern of weather that looks like snow.
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Hope that helps a little bit. Please don’t report me I tried.

8 0

3 years ago