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Y_Kistochka [10]
3 years ago
9

Suppose a skydiver (mass =100kg) is falling towards the earth. When the skydiver is 80 m above the earth he is moving at 60 m/s

at this point calculate the skydivers gravitational potential energy
Physics
1 answer:
attashe74 [19]3 years ago
7 0

Answer: 78400 J

Explanation:

The gravitational potential energy is the energy that a body or object possesses, due to its position in a gravitational field.  That is why this energy depends on the relative height of an object with respect to some point of reference and associated with the gravitational force.  

In the case of the Earth, in which the gravitational field is considered constant, the value of the gravitational potential energy U_{p} will be:  

U_{p}=mgh  

Where:

m=100 kg is the mass of the skydiver

g=9.8 m/s^{2} the acceleration due gravity

h=80 m the height of the skydiver

Hence:

U_{p}=(100 kg)(9.8 m/s^{2})(80 m)  

U_{p}=78400 J  

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"Find the equivalent resistance, the current supplied by the battery and the current through each resistor when the specified resistors are connected across a 20-V battery. Part (a) uses two resistors with resistance values that can be set with the animation sliders, and you can use the animation to verify your calculation. In part (b), three resistors are specified. (a) Two resistors are connected in series across a 20-V battery. Let R1 = 1 Ω and R2 = 2 Ω. Rea = (b) Add a third resistor to the circuit in series. Let R1 = 1 Ω, R2 = 2 Ω, and R3 = 3 Ω"

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For 2ohms resistor

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Since the same current flows through the resistors, the current across each of them is 3.33A

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V = IR

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V = 3.33×1

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V = 3.33×2

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For 3ohms resistor

V = 3.33×3

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