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Y_Kistochka [10]
3 years ago
9

Suppose a skydiver (mass =100kg) is falling towards the earth. When the skydiver is 80 m above the earth he is moving at 60 m/s

at this point calculate the skydivers gravitational potential energy
Physics
1 answer:
attashe74 [19]3 years ago
7 0

Answer: 78400 J

Explanation:

The gravitational potential energy is the energy that a body or object possesses, due to its position in a gravitational field.  That is why this energy depends on the relative height of an object with respect to some point of reference and associated with the gravitational force.  

In the case of the Earth, in which the gravitational field is considered constant, the value of the gravitational potential energy U_{p} will be:  

U_{p}=mgh  

Where:

m=100 kg is the mass of the skydiver

g=9.8 m/s^{2} the acceleration due gravity

h=80 m the height of the skydiver

Hence:

U_{p}=(100 kg)(9.8 m/s^{2})(80 m)  

U_{p}=78400 J  

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monitta

Answer:

The mass of the man is 71 kg

Explanation:

Given;

kinetic energy of the man, K.E = 887.5 J

velocity of the man, v = 5 m/s

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K.E = ¹/₂mv²

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m is the mass of the man

2K.E = mv²

m = 2K.E / v²

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Answer:

The observed frequency by the pedestrian is 424 Hz.

Explanation:

Given;

frequency of the source, Fs = 400 Hz

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Based on Doppler effect, as the car the approaches the stationary observer, the observed frequency will be higher than the transmitted (source) frequency because of decrease in distance between the car and the observer.

The observed frequency is calculated as;

F_s = F_o [\frac{v}{v_s + v} ] \\\\

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F₀ is the observed frequency

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Irina18 [472]
Given:
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