Question

When solid Ni metal is put into an aqueous solution of Pb(NO3)2, solid Pb metal and a solution of Ni(NO3)2 result. Write the net ionic equation for the reaction.

Answer 1

Answer:

$Pb^{2+}(aq)+Ni(s)\rightarrow Ni^{2+}(aq)+Pb(s)$

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary for us to write the complete molecular equation as shown below:

$Pb(NO_3)_2(aq)+Ni(s)\rightarrow Ni(NO_3)_2(aq)+Pb(s)$

Now, we can separate the nitrates in ions as they are aqueous to obtain:

$Pb^{2+}(aq)+2(NO_3)^-(aq)+Ni(s)\rightarrow Ni^{2+}(aq)+2(NO_3)^-(aq)+Pb(s)$

And then, we cancel out the nitrate ions as the spectator ones, for us to obtain the net ionic equation:

$Pb^{2+}(aq)+Ni(s)\rightarrow Ni^{2+}(aq)+Pb(s)$

Best regards!