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4 years ago

The compound AlCl3 contains how many atoms?

Chemistry

2 answers:

Pavel [41]4 years ago

7 0

Three chlorine and one aluminum

Ghella [55]4 years ago

3 0

The number of atoms of a compound can be determined by determining the subscripts used in each of the element involved. Then, adding these numbers. For this case, the subscript of aluminum (Al) is one which means there is only 1 aluminum atom. The subscript of chlorine (Cl) is 3 as there are 3 chlorine atoms. Therefore, the answer for this item is 4.

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Answer this question fast please!

MrRissso [65]

Answer:

A is a physical change, no atoms are being lost its still in it original form

B is a chemical change, it is losing atoms and changing into a new substance

Explanation:

5 0

3 years ago

Which is a method that can be used to separate the components of a solution?

sashaice [31]

Answer:

Distillation

Explanation:

i hope this helps

4 0

4 years ago

Which element, if combined with chlorine, will have the greatest attraction for the chlorine electrons?

tatiyna

As is correct my freind

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3 years ago

What is the overall cell potential for this redox reaction? Cd + Hg22+ → Cd2+ + 2Hg Given: Cd2+ + 2e− → Cd(s) = –0.40 and Hg22+

Hoochie [10]

Answer: 1.19 V

Explanation:

Standard potential for an electrochemical cell is given by:

$E^0{cell}$ = standard electrode potential = $E^0{cathode}-E^0{anode}$

The $E^0$ values have to be reduction potentials.

Given:

$E^o_{Cd^{2+}/Cd}=-0.40V$

$E^o_{Hg_2^{2+}/Hg}=0.79V$

$Cd+Hg_2^{2+}\rightarrow Cd^{2+}+2Hg$

Cadmium is losing electrons , undergo oxidation and thus act as anode. mercury is gaining electrons, undergo reduction and thus acts as cathode.

$E^0{cell}$ = standard electrode potential = $E^0{cathode}-E^0{anode}=0.79-(-0.40)=1.19V$

Thus the standard potential for an electrochemical cell with the cell reaction is 1.19 V.

4 0

3 years ago

Read 2 more answers

What is the fourth most abundant element in the universe in terms of mass?

iren [92.7K]

The fourth most abundant element in terms of mass is Carbon.

The first, second, and third most abundant element in terms of mass are Hydrogen, Helium, and Oxygen, respectively.

Hope this helps~

4 0

3 years ago

Read 2 more answers