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3 years ago

14

If you have two wires made out of the same material and the same thickness, one is 3-inches long and one is 6-inces long, which

one has the greater resistance?

1 answer:

Harlamova29_29 [7]3 years ago

8 0

Answer:

6 inces

Explanation:

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Which of the following statements is TRUE?

Karo-lina-s [1.5K]

Answer:

The correct option is E.

Explanation:

Average speed of the gas molecules = $v_a$

$v_a=\sqrt{\frac{2RT}{M}}$

T = Temperature of the gas molecule

M = molar mass of gas molecule

R = gas constant

$v_a\propto \frac{1}{M}$

Higher the molar mass of the molecule lesser will be the speed and vice versa.

Hence, statement A is not true.

Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

Larger the molar mass that larger the molecule lessor will be the effusion and vice versa.

Hence, statement B is not true.

According to Boyle's law, pressure of the gas is inversely proportional o the volume occupied by the gas at constant temperature. And same can also be observed from ideal gas law:

$PV=nRT$

$P=\frac{nRT}{V}$

$P\propto \frac{1}{V}$

Higher the pressure of the gas lower will be the volume occupied by the gas and vice versa.

Hence, statement C is not true.

With rise in temperature, effusion of gas molecule increase as kinetic energy of gas molecules increases in with increase in temperature.

Average kinetic energy is defined as the average of the kinetic energies of all the particles present in a system. It is determined by the equation:

$K=\frac{3RT}{2N_A}$

where,

K = Average kinetic energy

R = Gas constant

T = Temperature of the system

$N_A$ = Avogadro's number

$K\propto T$

Higher the temperature more will be kinetic energy of gas molecule more easily it will effuse.

Hence, statement D is not true.

From this we can conclude that out of five statements first 4 statements are not true which means that none of these statements are true.

3 0

4 years ago

What if you have a different number of protons in two atoms they are what?

Sunny_sXe [5.5K]

The answer is Elements

8 0

3 years ago

What does that number of protons tell you

bogdanovich [222]

The number of protons tells you which element the atom is. The number of protons is the element number (Hydrogen - 1, Helium - 2, etc.).

5 0

3 years ago

1). If the molarity of a KCl (potassium chloride) solution is 8.0 M, which of these is true?

Olin [163]

Q. No. 1 is Incomplete.

___________________________________________

Q. No.2: A saline solution contains 0.015 mol NaCl in exactly 0.10 L of solution. What is the molarity of the solution?

Answer:

Molarity = 0.15 mol.L⁻¹ (or) 0.15 M

Solution:

Molarity is the the unit of concentration and it is expressed as the amount of solute dissolved per unit volume of solution. It is expressed as,

Molarity = Moles / Volume of Solution (1)

Data Given;

Moles = 0.015 mol

Volume = 0.10 L

Now, putting value of Moles and Volume in eq. 1,

Molarity = 0.015 mol ÷ 0.10 L

Molarity = 0.15 mol.L⁻¹ (or) 0.15 M

___________________________________________

Q. No.3: A solution is prepared by dissolving 42.23 g of NH₄Cl into enough water to make 0.500 L of solution. Calculate its molarity.

Answer:

Molarity = 1.578 mol.L⁻¹ (or) 1.578 M

Solution:

Data Given;

Mass = 42.23 g

Volume = 0.50 L

M.Mass of NH₄Cl = 53.49 g/mol

First calculate Moles for given mass as,

Moles = Mass / M.mass

Moles = 42.23 g / 53.49 g.mol⁻¹

Moles = 0.789 mol

Formula used,

Molarity = Moles / Vol. of Solution ---- (1)

Now, putting value of Moles and Volume in eq. 1,

Molarity = 0.789 mol ÷ 0.50 L

Molarity = 1.578 mol.L⁻¹ (or) 1.578 M

___________________________________________

Q. No.4: Determine the concentration of a solution made by dissolving 10.0 g of sodium chloride (NaCl) in 0.75 L of solution.

Answer:

Molarity = 0.228 mol.L⁻¹ (or) 0.228 M

Solution:

Data Given;

Mass = 10.0 g

Volume = 0.75 L

M.Mass of NaCl = 58.44 g/mol

First calculate Moles for given mass as,

Moles = Mass / M.mass

Moles = 10.0 g / 58.44 g.mol⁻¹

Moles = 0.171 mol

Formula used,

Molarity = Moles / Vol. of Solution ---- (1)

Now, putting value of Moles and Volume in eq. 1,

Molarity = 0.171 mol ÷ 0.75 L

Molarity = 0.228 mol.L⁻¹ (or) 0.228 M

___________________________________________

Q. No.5: Determine the concentration of a solution made by dissolving 44.0 g of calcium chloride (CaCl₂) in 0.30 L of solution.

Answer:

Molarity = 1.32 mol.L⁻¹ (or) 1.32 M

Solution:

Data Given;

Mass = 44.0 g

Volume = 0.30 L

M.Mass of CaCl₂ = 110.98 g/mol

First calculate Moles for given mass as,

Moles = Mass / M.mass

Moles = 44.0 g / 110.98 g.mol⁻¹

Moles = 0.396 mol

Formula used,

Molarity = Moles / Vol. of Solution ---- (1)

Now, putting value of Moles and Volume in eq. 1,

Molarity = 0.396 mol ÷ 0.30 L

Molarity = 1.32 mol.L⁻¹ (or) 1.32 M

8 0

4 years ago

Can someone please help me i dont understand and im about to get a zero

enyata [817]

Is this a test or something else?

6 0

4 years ago