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2 years ago

9

If a single one of these can be answered, can someone help me? I put my book somewhere. I’ll mark brainliest to actual answers :

))

2 answers:

olchik [2.2K]2 years ago

8 0

Aerobic means to use oxygen. Organisms use this process because they utilize oxygen to convert fuel into energy.

Alisiya [41]2 years ago

5 0

16. Anaerobic means Without oxygen

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the only difference between an isosoleces trapezoidand parallel trapezoid are that the non-parellel sides are congruent

ludmilkaskok [199]

Is this a true or false type of question

4 0

3 years ago

What is 7 1/8 times 2 5/6

Otrada [13]

Answer:

20 and 3/16

Step-by-step explanation:

Answer:

578×176=20316

Solution with Steps

578×176=?

For fraction multiplication, multiply the numerators and then multiply the denominators to get

57×178×6=96948

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 969 and 48 using

GCF(969,48) = 3

969÷348÷3=32316

The fraction

32316

is the same as

323÷16

Convert to a mixed number using

long division for 323 ÷ 16 = 20R3, so

32316=20316

Therefore:

578×176=20316

Solution by Formulas

Apply the fractions formula for multiplication, to

578×176

and solve

57×178×6

=96948

Reduce by dividing both the numerator and denominator by the Greatest Common Factor GCF(969,48) = 3

969÷348÷3=32316

Convert to a mixed number using

long division for 323 ÷ 16 = 20R3, so

32316=20316

Therefore:

578×176=20316

7 0

3 years ago

Round 14.603 to the nearest hundredth

Finger [1]

The answer is 14.60. Hope this helps!

7 0

3 years ago

Read 2 more answers

An article presents voltage measurements for a sample of 66 industrial networks in Estonia. Assume the rated voltage for these n

kramer

Answer:

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 232 V

Sample mean, $\bar{x}$ = 231.5 V

Sample size, n = 66

Sample standard deviation, s = 2.19 V

Alpha, α = 0.05

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 232\\H_A: \mu \neq 232$

We use Two-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n-1}} }$ Putting all the values, we have

$t_{stat} = \displaystyle\frac{231.5- 232}{\frac{2.19}{\sqrt{66}} } = -1.8548$

Now,

$t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = \pm 1.9971$

Since,

$|t_{stat}| > |t_{critical}|$

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

4 0

2 years ago

Tickets for a concert were \$5$5dollar sign, 5 for each child and \$8$8dollar sign, 8 for each adult. At one of the concerts, ea

OlgaM077 [116]

Answer:

Step-by-step explanation:

Let c represent the number of children that attended the concert.

Let a represent the number of adults that attended the concert.

At one of the concerts, each adult brought 4 children with them, and 10 children attended without an adult. This means that the number of children that attended is

c = 4a + 10

Tickets for a concert were $5 for each child and $8 for each adult. The total ticket sales were $1730. It means that

5c + 8a = 1730

Therefore, the systems of equations that can be solved to determine the number of children, c, and adults that attended the concert is

c = 4a + 10

5c + 8a = 1730

4 0

3 years ago