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2 years ago

PLEASE HELP DUE in a couple minutes.

Mathematics

2 answers:

kodGreya [7K]2 years ago

7 0

Answer:

I think it's the last one(-6,9) or the third one(6,-1)

Step-by-step explanation:

Nuetrik [128]2 years ago

6 0

Answer:

The last one, (-6,9)

Step-by-step explanation: For it to be right the nine would have to be negative.

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Robert works in a toll booth. About 18 to 23 cars pass through Robert's booth every 23 minutes. Which is a reasonable estimate f

BARSIC [14]

A reasonable number between 18 and 23 is 20. 69 minutes is 3 times 23 minutes, so we multiply the 20 by 3, getting an estimate of 60 cars.

8 0

3 years ago

Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).

NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

$1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}$

Now, differentiate to obtain

$\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}$

$=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}$

To obtain the required form, extract a factor in both the numerator and denominator:

$\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)$

3 0

3 years ago

What is the value of X ?

Katyanochek1 [597]

Answer:

X=84

Step-by-step explanation:

180(the sum of the interior triangle angles) - [(180-130)+(180-134)]

6 0

3 years ago

Two years ago, Sally had 5,000 dogs in her dog shelter. Now she has 24,575 dogs. What is the

vodomira [7]

Two years ago, Sally had 5,000 dogs in her dog shelter. Now she has 24,575 dogs. The rate of change is 391.5 % increase

<em><u>Solution:</u></em>

Given that Two years ago, Sally had 5,000 dogs in her dog shelter

Now she has 24,575 dogs

To find: rate of change

A rate of change is a rate that describes how one quantity changes in relation to another quantity

<h3><u>Steps to follow:</u></h3>

First: work out the difference (increase) between the two numbers you are comparing.

Increase = New Number - Original Number.

Then: divide the increase by the original number and multiply the answer by 100.

% change = Increase ÷ Original Number x 100

$\text {rate of change }=\frac{\text { new value }-\text {original value}}{\text {original value}} \times 100$

$\begin{array}{l}{\text { rate of change }=\frac{24,575-5000}{5000} \times 100} \\\\ {\text { rate of change }=\frac{19575}{5000} \times 100=391.5}\end{array}$

Thus the rate of change is 391.5 % increase

5 0

3 years ago

Can someone please help me with this one? I’m very confused, how can you solve for the width if the problem doesn’t tell you wha

Marizza181 [45]

Answer:

A. (2x-3)/2

Step-by-step explanation:

Performing the long division indicated by the perimeter expression, you find ...

perimeter = (2x -3) + (10x +6)/(x^2 +2x)

Comparing this to the formula for the perimeter ...

perimeter = 2W +2L

where L is said to be of the form (ax +b)/(x^2 +2x)

we can match terms in the perimeter expression to see that ...

2W = 2x -3

2L = (10x +6)/(x^2 +2x)

The problem doesn't ask for it, but we can see that (a, b) = (5, 3). We can also see that ...

W = (2x -3)/2 . . . . . . . matches choice A

4 0

3 years ago