Rearrange equation.h=-16t^2-6t+110 h = 0 at the ground. divide both sides of the equation by (-2) to yield: 0 = 8t^2+3t - 55 and use quadratic equation h=<span>-b±√(b2 - 4ac)</span> 2awhere a = 8, b= 3, c=-55 Substitute: [-3 ± √(9 - 4*8*(-55))] / (16) = [6 ± √(36 + 1760)] / (16) = [6 ± √(1796)] /16 = (6 ± 42.3792)/16. Time can only be positive for this problem...so discard negative answer. = 48.3792/16 = 3.02 seconds
Simple you get the area of the inner rectangle, then the area of the 2 semi circles then add them.
First, you need to notice that the diameter of each circle is same as the side of the rectangle (46m), also not that the 2 semi circles will make a complete one circle with radius (46/2)
so now we are left with the area of the rectangle+the area of a circle with radius of 32m
The total area= (46*92)+(3.14*(32^2))= 7447.36m^2
and to keep you significant figures the answer is rounded to 3 digits, so the final answer will be 745m^2.
Hope this helps, thanks.
Perimeter of rectangle=66
length of rectangle=L
width of rectangle=w
P of a rect.= 2(length)+ 2(width)
66= 2L+2w
if the length is 7in more than the width, then
L=7+w
Now we will substitute 7+w in for L. Here is our new equation:
66=2(7+w) + 2w
Solve for w
66=14+2w+2w
66=14+4w
52=4w
w=13
L=7+13, so L=20
I hooe this is explained well enough
Answer:
d = 
Step-by-step explanation:
1) To solve for d, isolate it in the equation. So, to get rid of the 
with the d, add 
to both sides.
Thus, d = .
The slope intercept form is y = mx + c.
The quantity given by the constant term c, is the vertical or y intercept.
It is the point where the line cuts the y axis, and this point, x = 0.
