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3 years ago

HELP PLEASE THANK YOU

Mathematics

1 answer:

vova2212 [387]3 years ago

3 0

Answer: A (b and F) They share the 90 degree angle and its just flipped

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Which statement BEST describes the graph of f(x - 6)?

Alex

Answer:

B. f(x) is shifted left by 6 units

Step-by-step explanation:

when we talk about translations, we know they happen along the X axis, y axis or sometimes both, in this case we see that were subtracting x by six units, so we are moving left along the x axis

ways to remember this is:

-you count up x the RIGHT way going right

-you count UP y

and of cource by process of ellimination we know that decreasing X goes left and decreasing y goes down

ALSO NOTE: x always goes horizontally and y always goes vertically

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2 years ago

Lines j, k, m, and n lie in a plane. You know line j is perpendicular to line n, m is perpendicular to line n, and line k is par

Alex_Xolod [135]

B it is no problem I don't think it's that answer but yea

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3 years ago

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Why did the 30-60-90 triangle marry the 45-45-90 triangle

Tatiana [17]

Answer: because they were right for each other.

Step-by-step explanation:

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4 years ago

1) find the equation of the line parallel to

In-s [12.5K]

Answer:

1) The equation of the line parallel to x-5y=6 and through (4,-2) is 5y = x -14

2) The equation of the line perpendicular to y= -2/5x + 3 and through (2,-1) is 2y = 5x -12

Solution:

1) find the equation of the line parallel to x-5y=6 and through (4,-2).

Given, line equation is x – 5y = 6

We have to find the line equation that is parallel to given line and passing through the point (4, -2)

Now, let us find slope of the given line.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-5}=\frac{1}{5}$

Now, we know that, slope of parallel lines are equal.

So, slope of required line is 1/5 and it passes through (4, -2)

Now, using point slope form

$y-y_{1}=m\left(x-x_{1}\right) \text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on line. }$

$y-(-2)=\frac{1}{5}(x-4) \rightarrow 5(y+2)=x-4 \rightarrow 5 y+10=x-4 \rightarrow x-5 y=14$

Hence, the line equation is 5y = x -14

2) find the equation of the line perpendicular to y= -2/5x + 3 and through (2,-1)

$\text { Given, line equation is } y=-\frac{2}{5} x+3 \rightarrow 5 y=-2 x+15 \rightarrow 2 x+5 y=15$

We have to find the line equation that is perpendicular to given line and passing through the point (2, -1)

Now, let us find slope of the given line.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-2}{5}=-\frac{2}{5}$

Now, we know that, product of slopes of perpendicular lines equals to -1.

So, slope of required line $\times$ slope of given line = -1

slope of required line = $-1 \times \frac{5}{-2}=\frac{5}{2}$

And it passes through (2, -1)

Now, using point slope form

$\begin{array}{l}{\text { Line equation is } y-(-1)=\frac{5}{2}(x-2) \rightarrow 2(y+1)=5(x-2)} \\\\ {\rightarrow 2 y+2=5 x-10 \rightarrow 5 x-2 y=12}\end{array}$

Hence, the line equation is 2y = 5x -12

4 0

3 years ago

7x10^7 in standard form

Nikolay [14]

70000000 the reason that this is the answer to this is because if multiply 10 by 7 you will have 70 and just add 6 zeros

4 0

3 years ago