When you multiply a same number but with different powers, you can simply add the powers together. So, in your question, add the powers -1 and -7 together.
7^(-1) x 7^(-7) = 7^(-8)

When you divide a same number but with different powers, you subtract the power at the top with the power from the denominator. So, -8 - (-7) = -1.
7^(-8) / 7^(-7) = 7^(-1)

So your answer would be 7^(-1).
Hopefully my explanation was clear?

5 0

3 years ago

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( 7x + 1/2) + ( 7x - 7 and 1/2) Simplify

pishuonlain [190]

Answer:

The answer will be 7(2x - 1)

Step-by-step explanation:

1) Convert 7 and 1/2 to improper fraction. Use this rule: a b/c = ac + b/c

$7x + \frac{1}{2} + 7x - \frac{7 \times 2 + 1}{2}$

2) Simplify 7 × 2 to 14 .

$7x + \frac{1}{2} + 7x - \frac{14 + 1}{2}$

3) Simplify 14 + 1 to 15.

$7x + \frac{1}{2} + 7x - \frac{15}{2}$

4) Collect like terms.

$(7x + 7x) + ( \frac{1}{2} - \frac{15}{2} )$

5) simplify.

$14x - 7$

6) Factor out the common term 7.

$7(2x - 1)$

Therefor, the answer is 7( 2x - 1 ).

7 0

3 years ago

Write the expression as a square of a monomial.

frozen [14]

Answer:

The square of a monomial is $(9x^2)^2$

Step-by-step explanation:

Consider the provided monomial.

$81x^4$

We need to Write the expression as a square of a monomial.

The above expression can be written as:

$9\times 9\times x^2\times x^2$

$9^2(x^2)^2$

$(9x^2)^2$

Hence, the square of a monomial is $(9x^2)^2$

8 0

3 years ago

What is 0.4(5+2x)-0.5=3(0.3x+0.7) I've solved this but I'm not sure I got the right answer

BlackZzzverrR [31]

If you have a graphing calculator one way to know you are right is put the left side in Y1 and the right side in Y2 then hit 2nd trace and intersection then find the intersection and the X value is your answer. If you don't have a graphing calculator then I'm sorry

5 0

3 years ago

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