Given:
frequency, f = 60.0 Hz
frequency, f' = 45.0 Hz
Solution:
To calculate max current in inductor, :
At f = 60.0 Hz
L = 0.1326 H
Now, reactance at f' = 45.0 Hz:
Now, is given by:
Therefore, max current in the inductor, = 2.13 A
Materials to be used to build a watch tower
1 answer:
You might be interested in
Answer:
The population size would be
The yield would be
Explanation:
So in this problem we are going to be examining the application of a population dynamics a fishing pond and stock fishing and objective would be to obtain the maximum sustainable yield and and the population of the fish at the obtained maximum sustainable yield, so basically we would be applying an engineering solution to fishing
So the current yield which is mathematically represented as
Where dN is the change in the number of fish
and dt is the change in time
So in order to obtain the solution we need to obtain the rate of growth
For this we would be making use of the growth rate equation which is
Where N is the population of the fish which is given as 4,000 fishes
and K is the carrying capacity which is given as 10,000 fishes
r is the growth rate
Substituting these values into the equation
The maximum sustainable yield would be dependent on the growth rate an the carrying capacity and this mathematically represented as
So since the maximum sustainable yield is 2082 then the the population need to be higher than 4,000 so in order to ensure a that this maximum yield the population size denoted by would be
Answer:
a) The ductility = -30.12%
the negative sign means reduction
Therefore, there is 30.12% reduction
b) the true stress at fracture is 658.26 Mpa
Explanation:
Given that;
Original diameter = 12.8 mm
Final diameter = 10.7
Engineering stress = 460 Mpa
a) determine The ductility in terms of percent reduction in area;
Ai = π/4( )² ; Ag = π/4(
)²
% = π/4 [ ( ( )² - (
)²) / ( π/4 (
)²) ]
= ( ( )² - (
)²) / (
)² × 100
we substitute
= [( (10.7)² - (12.8)²) / (12.8)² ] × 100
= [(114.49 - 163.84) / 163.84 ] × 100
= - 0.3012 × 100
= -30.12%
the negative sign means reduction
Therefore, there is 30.12% reduction
b) The true stress at fracture;
True stress =
( 1 +
)
is engineering strain
= dL / Lo
= (do² - df²) / df² = (12.8² - 10.7²) / 10.7² = (163.84 - 114.49) / 114.49
= 49.35 / 114.49
= 0.431
so we substitute the value of into our initial equation;
True stress = 460 ( 1 + 0.431)
True stress = 460 (1.431)
True stress = 658.26 Mpa
Therefore, the true stress at fracture is 658.26 Mpa