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Readme [11.4K]
2 years ago
9

Materials to be used to build a watch tower​

Engineering
1 answer:
gizmo_the_mogwai [7]2 years ago
8 0

Answer:

Wood, brick or stone. I you want to make it for a school project then you can use sticks.

Hope it helps!!!

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Select the correct answer. Jennifer, a construction manager at a construction firm, has to hire several contractors and subcontr
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: Câu nào dưới đây thể hiện sự thiếu tự chủ?
sukhopar [10]

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thành thật mà nói bởi vì cách những chiếc lá đang chuyển và cách mặt trời chiếu sáng.

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2 years ago
Identify and describe the three stages of a life cycle analysis.
sesenic [268]
The LCA process is a systematic, phased approach and consists of four components: goal definition and scoping, inventory analysis, impact assessment, and interpretation. The standards are provided by the International Organisation for Standardisation (ISO) in ISO 14040 and 14044, and describe the four main phases of an LCA: Goal and scope definition. Inventory analysis. Impact assessment.

Hope this is helpful
5 0
2 years ago
If two statements are inconsistent with each other, at least one of them must be false. a)-True b)-False
olchik [2.2K]

Answer:

a)- True

Explanation:

If two statements are inconsistent with each other it means that they are not telling the same, if they are not telling the same it means that only one of them COULD be true, but there is a third option where the two statements are wrong and non statement is telling the true...so:

If we have two statements inconsistent with each other, AT LEAST one of the statements is false.

7 0
3 years ago
Determine the change in the enthalpy of helium, in kJ/kg, as it undergoes a change of state from 100 kPa and 20 oC to 600 kPa an
MatroZZZ [7]

Answer:

The change in enthalpy of helium is 4073.86kJ/kg

Explanation:

∆H = Cp(T2 - T1)

Cp = 3.5R = 3.5×8.314 = 29.099kJ/kgmolK ÷ 2 (1kgmol of helium = 2kg of helium) = 14.5495kJ/kgK, T2 = 300°C = 300+273K = 573K, T1 = 20°C = 20+273K = 293K

∆H = 14.5495kJ/kgK(573K - 293K) = 14.5495kJ/kgK × 280K = 4073.86kJ/kg

7 0
3 years ago
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