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avanturin [10]
3 years ago
13

Can somebody help me with that

Engineering
1 answer:
skelet666 [1.2K]3 years ago
4 0

Answer:

I think it's 23 ohms.

Explanation:

Not entirely sure about it.

hope this helps

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When you first start a car after it has been sitting for more than an hour, it pollutes up to ......times more than when the eng
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20 time more then when it’s warm
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4 years ago
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Given a square matrix [A], write a single line MATLAB command that will create a new matrix [Aug] that consists of the original
Liono4ka [1.6K]

Answer:

Consider A is square matrix of order 4 x 4 generated using magic function. Augmented matrix can be generated using:

Aug=[A eye(size(A))]

Above command is tested in MATLAB command window and is attached in figure below

8 0
3 years ago
Convert 850 nm wavelength into frequency, eV, wavenumber, joules and ergs.
Sholpan [36]

Answer:

Frequency = 3.5294\times 10^{14}s^{-1}

Wavenumber = 1.1765\times 10^6m^{-1}

Energy = 2.3365\times 10^{-19}J

Energy = 1.4579 eV

Energy = 2.3365\times 10^{-12}erg

Explanation:

As we are given the wavelength = 850 nm

conversion used : (1nm=10^{-9}m)

So, wavelength is  850\times 10^{-9}m

The relation between frequency and wavelength is shown below as:

Frequency=\frac{c}{Wavelength}

Where, c is the speed of light having value = 3\times 10^8m/s

So, Frequency is:

Frequency=\frac{3\times 10^8m/s}{850\times 10^{-9}m}

Frequency=3.5294\times 10^{14}s^{-1}

Wavenumber is the reciprocal of wavelength.  

So,  

Wavenumber=\frac{1}{Wavelength}=\frac{1}{850\times 10^{-9}m}

Wavenumber=1.1765\times 10^6m^{-1}

Also,  

Energy=h\times frequency

where, h is Plank's constant having value as 6.62\times 10^{-34}J.s

So,  

Energy=(6.62\times 10^{-34}J.s)\times (3.5294\times 10^{14}s^{-1})

Energy=2.3365\times 10^{-19}J

Also,  

1J=6.24\times 10^{18}eV

So,  

Energy=(2.3365\times 10^{-19})\times (6.24\times 10^{18}eV)

Energy=1.4579eV

Also,  

1J=10^7erg

So,  

Energy=(2.3365\times 10^{-19})\times 10^7erg

Energy=2.3365\times 10^{-12}erg

5 0
3 years ago
Make Routh tables and tell how many roots of the following two polynomials are in the right half plane and in the left half plan
12345 [234]

Answer:  

P(s) = s5 + 3s4 + 5s3 + 4s2 + s

For above Polynomial, there are two RHP Poles & Three LHP Poles.

& for the Second Polynomial,

P(s)=3s7 + 9s6 + 6s5 + 4s4 + 7s3 + 8s2 + 2s + 6

For this Polynomial, there are Four RHP Poles & Three LHP Poles.

Explanation:

As the equation is given by for the first polynomial,

P(s)=s5 + 3s4 + 5s3 + 4s2 + s

The Routh table is attached in the attachment, & from that table we can see that there are two sign changes for thuis first ploynomial. Moreover, there are two RHP poles & Three LHP Poles.

Similarly the equation for the second polynomial is given by as,

P(s)=3s7 + 9s6 + 6s5 + 4s4 + 7s3 + 8s2 + 2s + 6

The Routh Table is attached in the same attachment below in the 2nd slide & from this table we can see that there are four sign changes for this polynomial while it includes Four RHP Poles & three LHP Poles.

Download pptx
3 0
3 years ago
(a) Briefly explain what is meant by threshold effect in FM receivers. Why is this effect not present in PM receivers?
Vedmedyk [2.9K]

Answer:

heeeheeee

Explanation:

6 0
3 years ago
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