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Nikolay [14]
3 years ago
8

8. In a closed hydraulic brake system, the hydraulic pressure:

Engineering
2 answers:
beks73 [17]3 years ago
8 0

Answer:

Option A is correct.

The hydraulic pressure in a closed hydraulic brake system is constant.

Explanation:

The hydraulic brake system works on the principle of pressure transmission. It is termed a closed hydraulic brake system when there is no leakage of fluid all through the setup. The transmission works on the basis of Pascal's law for pressure and it explains that pressure applied to a fluid is transmitted undiminished to every part of the fluid.

The force applied on the brake pedals by the driver at the controlling end of the hydraulic system is transmitted by the pushrod on the piston(s) in the master cylinder.

This causes fluid from the brake fluid reservoir to flow into a pressure chamber. This in turn causes an increase in the pressure of the entire hydraulic system, forcing fluid through the hydraulic lines toward the caliper(s) where it then acts upon the caliper piston(s).

The force applied on the brakes pedal, F₁,

is applied on the cross sectional Area of the master piston, A₁ and this is transmitted in terms of pressure by the fluid (with no loss in pressure, that is, constant pressure, if the hydraulic braking system is especially a closed one) through the callipers to the calliper(s) pistons.

Hope this Helps!!!

DiKsa [7]3 years ago
3 0

Answer:

A. Is constant

Explanation:

This is in accordance with pascal's law of pressure that states the hydraulic pressure in a fluid is transmitted undiminished to every portion of the fluid.

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A sign erected on uneven ground is guyed by cables EF and EG. If the force exerted by cable EF at E is 46 lb, determine the mome
Vikki [24]

Answer:

M_AD = 1359.17 lb-in

Explanation:

Given:

- T_ef = 46 lb

Find:

- Moment of that force T_ef about the line joining points A and D.

Solution:

- Find the position of point E:

                           mag(BC) = sqrt ( 48^2 + 36^2) = 60 in

                           BE / BC = 45 / 60 = 0.75

Hence,                E = < 0.75*48 , 96 , 36*0.75> = < 36 , 96 , 27 > in

- Find unit vector EF:

                           mag(EF) = sqrt ( (21-36)^2 + (96+14)^2 + (57-27)^2 ) = 115 in

                           vec(EF) = < -15 , -110 , 30 >

                           unit(EF) = (1/115) * < -15 , -110 , 30 >

- Tension            T_EF = (46/115) * < -15 , -110 , 30 > = < -6 , -44 , 12 > lb

- Find unit vector AD:

                           mag(AD) = sqrt ( (48)^2 + (-12)^2 + (36)^2 ) = 12*sqrt(26) in

                           vec(AD) = < 48 , -12 , 36 >

                           unit(AD) = (1/12*sqrt(26)) * < 48 , -12 , 36 >

                           unit (AD) = <0.7845 , -0.19612 , 0.58835 >

Next:

                           M_AD = unit(AD) . ( E x T_EF)

                           M_d = \left[\begin{array}{ccc}0.7845&-0.19612&0.58835\\36&96&27\\-6&-44&12\end{array}\right]

                            M_AD = 1835.73 + 116.49528 - 593.0568

                            M_AD = 1359.17 lb-in

3 0
3 years ago
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