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3 years ago

8. In a closed hydraulic brake system, the hydraulic pressure:

Engineering

2 answers:

beks73 [17]3 years ago

8 0

Answer:

Option A is correct.

The hydraulic pressure in a closed hydraulic brake system is constant.

Explanation:

The hydraulic brake system works on the principle of pressure transmission. It is termed a closed hydraulic brake system when there is no leakage of fluid all through the setup. The transmission works on the basis of Pascal's law for pressure and it explains that pressure applied to a fluid is transmitted undiminished to every part of the fluid.

The force applied on the brake pedals by the driver at the controlling end of the hydraulic system is transmitted by the pushrod on the piston(s) in the master cylinder.

This causes fluid from the brake fluid reservoir to flow into a pressure chamber. This in turn causes an increase in the pressure of the entire hydraulic system, forcing fluid through the hydraulic lines toward the caliper(s) where it then acts upon the caliper piston(s).

The force applied on the brakes pedal, F₁,

is applied on the cross sectional Area of the master piston, A₁ and this is transmitted in terms of pressure by the fluid (with no loss in pressure, that is, constant pressure, if the hydraulic braking system is especially a closed one) through the callipers to the calliper(s) pistons.

Hope this Helps!!!

DiKsa [7]3 years ago

3 0

Answer:

A. Is constant

Explanation:

This is in accordance with pascal's law of pressure that states the hydraulic pressure in a fluid is transmitted undiminished to every portion of the fluid.

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An existing building is suffering from cracks in the exterior walls. The investigating engineer wants to ensure that the foundat

jek_recluse [69]

Answer:

$18 ft^{2}$

Explanation:

Soil bearing pressure= $\frac {Load}{Area}$

Since we're given pressure of 2500 psf and load of 45000 pounds

The area= $\frac {45000}{2500}=18$

Therefore, the smallest area of safe footings should not be less than $18 ft^{2}$

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3 years ago

A 3.5-m3 rigid tank initially contains air whose density is 2 kg/m3 . The tank is connected to a high-pressure supply line throu

Mumz [18]

Answer:

Explanation:

First, we find the mass of the air originally in the tank.

Density is given as mass divided by volume. It is given as:

$Density = \frac{mass}{volume}$

Therefore, mass is:

$mass = denisty *volume$

Density of air = $2 kg/m^3$ ; Volume of the tank = $3.5 m^3$

$=> Mass = 3.5 * 2 = 7 kg$

The mass of the air initially in the tank is 7 kg.

After air is allowed to enter, the mass changes.

New density = $6.5 kg/m^3$

The new mass will be:

$Mass = 6.5 * 3.5 = 22.75 kg$

We can now find the mass of air that has entered the tank:

Mass of air that entered tank = New mass of air - Original mass of air

M = 22.75 - 7.0 = 15.75 kg

The mass of air that entered the tank is 15.75 kg.

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3 years ago

5. Assume that you and your best friend ench have $1000 to invest. You invest your money

Bezzdna [24]

Correct question reads;

Assume that you and your best friend each have $1000 to invest. You invest your money in a fund that pays 10% per year compound interest. Your friend invests her money at a bank that pays 10% per year simple interest. At the end of 1 year, the difference in the total amount for each of you is:

(a) You have $10 more than she does

(b) You have $100 more than she does

(d) She has $10 more than you do

Answer:

(d) She has $10 more than you do

Explanation:

Using the compound interest formula

A= P [ (1-i)^n-1

Where P = Principal/invested amount, i = annual interest rate in percentage, and n = number of compounding periods.

My compound interest is:

= 1000 [ (1-0.1)^1-1

= $1000

$1,000 + $1,000 invested= $2,000 total amount received.

My friend's simple interest is;

To determine the total amount accrued we use the formula:

P(1 + rt) Where:

P = Invested Amount (1000)

I = Interest Amount (10,000)

r = Rate of Interest per year (10% or 0.2)

t = Time Period (1 )

= 1000 (1 + rt)

= 1000 (1 + 0.1x1)

= $1100 + $1000 invested = $2100 total amount received.

Therefore, we observe that she (my friend) has $100 more than I do.

5 0

3 years ago

Balanced forces will result in which of the following

tia_tia [17]

D is the answer. Hope this helped

8 0

3 years ago

A material point in equilibrium has 1 independent component of shear stress in the xz plane. a)True b)- False

ozzi

Answer:

True

Explanation:

For point in xz plane the stress tensor is given by $\left[\begin{array}{ccc}Dx_{} &txz\\tzx&Dz\\\end{array}\right]$

where Dx is the direct stress along x ; Dz is direct stress along z ; tzx and txz are the shear stress components

We know that the stress tensor matrix is symmetrical which means that tzx = txz ( obtained by moment equlibrium )

thus we require only 1 independent component of shear stress to define the whole stress tensor at a point in 2D plane

8 0

2 years ago