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TiliK225 [7]
3 years ago
5

Define extensive and intensive properties of thermodynamic system.

Engineering
2 answers:
Flura [38]3 years ago
7 0

Answer:

An intense property is a physical attribute of a system that is independent of the size of the system or the quantity of material it contains. An extensive property of a system, on the other hand, is dependent on the size of the system or the amount of material in it.

Explanation:

kow [346]3 years ago
3 0
Thermodynamic properties can be divided into two general classes, intensive and extensive properties. An intensive property is independent of the amount of mass. The value of an extensive property varies directly with the mass. Thus, if a quantity of matter in a given state is divided into two equal parts, each part will have the same value of intensive property as the original and half the value of the extensive property. Temperature, pressure, specific volume,and density are examples of intensive properties. Mass and total volume are examples of extensive properties.
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Proper handling of blueprints includes which of the following
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folding plans neatly after use

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Select the correct answer.
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A is the correct answer
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A tensile test is performed on a metal specimen, and it is found that a true plastic strain of 0.20 is produced when a true stre
disa [49]

Answer:

0.234

Explanation:

True stress is ratio of instantaneous load acting on instantaneous cross-sectional area

σ = k × (ε)^n  

σ = true stress

ε = true strain

k = strength coefficient

n = strain hardening exponent

ε = ( σ / k) ^1/n

take log of both side

log ε = \frac{1}{n} ( log σ  - log k)

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6 0
3 years ago
Read 2 more answers
If the same type of thermoplastic polymer is being tensile tested and the strain rate is increased, it will: g
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Answer:

It would break I think need to try it out

Explanation:

3 0
2 years ago
3. A 4-m × 5-m × 7-m room is heated by the radiator of a steam-heating system. The steam radiator transfers heat at a rate of 10
Natali [406]

Answer:

14.52 minutes

<u>OR</u>

14 minutes and 31 seconds

Explanation:

Let's first start by mentioning the specific heat of air at constant volume. We consider constant volume and NOT constant pressure because the volume of the room remains constant while pressure may vary.

Specific heat at constant volume at 27°C = 0.718 kJ/kg*K

Initial temperature of room (in kelvin) = 283.15 K

Final temperature (required) of room = 293.15 K

Mass of air in room= volume * density= (4 * 5 * 7) * (1.204 kg/m3) = 168.56kg

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Heat required = 0.718 * (293.15 - 283.15) * (168.56) = 1,210.26 kJ

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3 years ago
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