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3 years ago

What is the volume of this cone?

Mathematics

2 answers:

Romashka-Z-Leto [24]3 years ago

8 0

Answer:

3537.73 cubic in

Step-by-step explanation:

Given,

Diameter of the cone = 26 in

Radius of the cone = 26in ÷ 2 = 13 in

Height of the cone = 20 in

Therefore, volume of the cone

$= \frac{1}{3} \pi {r}^{2} h$

$= \frac{1}{3} \times 3.14 \times 13 \times 13 \times 20$

$= 3,537.7333333333 \: {in}^{3}$

<u>Approx. 3537 . 73 cubic in (Ans)</u>

Alekssandra [29.7K]3 years ago

7 0

Uh the answer would be 3537.73

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7th GRADE MATH WILL GIVE BRAINLIEST 20 POINTS

tigry1 [53]

Answer:

I will say C, because tossing a coin twice has two outcomes. H is for heads while T is for heads. Tell me if I'm right.

Step-by-step explanation:

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3 years ago

The table below gives the dimensions of a bridge and a scale model of the bridgeFind the scale factor of the model to the real b

Oksana_A [137]

The corresponding sides of the model and the actual bridge are in proportion because the two solids are similar.

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3 years ago

An SRS of 350 high school seniors gained an average of x¯=21 points in their second attempt at the SAT Mathematics exam. Assume

Lynna [10]

Answer:

a) $21-2.58\frac{52}{\sqrt{350}}=13.83$

$21+2.58\frac{52}{\sqrt{350}}=28.17$

So on this case the 99% confidence interval would be given by (13.83;28.17)

b) $ME=2.58\frac{52}{\sqrt{350}}=7.17$

c) $ME=2.58\frac{52}{\sqrt{100}}=13.42$

d) D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part a

$\bar X=21$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=52$ represent the population standard deviation

n=350 represent the sample size

99% confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$

Now we have everything in order to replace into formula (1):

$21-2.58\frac{52}{\sqrt{350}}=13.83$

$21+2.58\frac{52}{\sqrt{350}}=28.17$

So on this case the 99% confidence interval would be given by (13.83;28.17)

Part b

The margin of error is given by:

$ME=2.58\frac{52}{\sqrt{350}}=7.17$

Part c

The margin of error is given by:

$ME=2.58\frac{52}{\sqrt{100}}=13.42$

Part d

As we can see when we reduce the sample size we increase the margin of error so the best option for this case is:

D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

6 0

3 years ago

What is the nearest tenth of .8215?

riadik2000 [5.3K]

Answer:

The answer to this would be .8

Step-by-step explanation:

A tenth is only one figure, and due to the rule of "5 and above give it a shove; 4 and below let it go", this number would round to 0.8.

8 0

3 years ago

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madreJ [45]

Answer

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Step-by-step explanation:

You must find the unit rate. To do so, you must divide 3.90 by 15. That will give you 0.26. After, times 6 and .26 to get your answer. Hope this helps.

8 0

3 years ago